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DiKsa [7]
3 years ago
13

El volumen de un cubo, cuyos lados miden 4,5 cm corresponde a: A- 91 cm2 B- 91,1 cm C- 91 cm3

Mathematics
1 answer:
Leya [2.2K]3 years ago
6 0

Answer:

La respuesta correcta es la opción C: 91 cm³.

Step-by-step explanation:

La fórmula del volumen de un cubo es la siguiente:

V = a^{3}

En dónde:

a: es cada lado del cubo = 4,5 cm

Entonces, el volumen del cubo es:

V = a^{3} = (4,5 cm)^{3} = 91.1 cm^{3} \approx 91 cm^{3}

Por lo tanto, la respuesta correcta es la opción C: 91 cm³.  

Espero que te sea de utilidad!

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A certain number of sixes and nines is added to give a sum of 126; if the number of sixes and nines is interchanged, the new sum
galina1969 [7]

Answer:

Original number of sixes = 6

Original number of nines = 10

Step-by-step explanation:

We are told in the question that:

A certain number of sixes and nines is added to give a sum of 126

Let us represent originally

the number of sixes = a

the number of nines = b

Hence:

6 × a + 9 × b = 126

6a + 9b = 126.....Equation 1

If the number of sixes and nines is interchanged, the new sum is 114.

For this second part, because it is interchanged,

Let us represent

the number of sixes = b

the number of nines = a

6 × b + 9 × a = 114

6b + 9a = 114.......Equation 2

9a + 6b = 114 .......Equation 2

6a + 9b = 126.....Equation 1

9a + 6b = 114 .......Equation 2

We solve using Elimination method

Multiply Equation 1 by the coefficient of a in Equation 2

Multiply Equation 2 by the coefficient of a in Equation 1

6a + 9b = 126.....Equation 1 × 9

9a + 6b = 114 .......Equation 2 × 6

54a + 81b = 1134 ........ Equation 3

54a + 36b = 684.........Equation 4

Subtract Equation 4 from Equation 3

= 45b = 450

divide both sides by b

45b/45 = 450/45

b = 10

Therefore, since the original the number of nines = b,

Original number of nines = 10

Also, to find the original number of sixes = a

We substitute 10 for b in Equation 1

6a + 9b = 126.....Equation 1

6a + 9 × 10 = 126

6a + 90 = 126

6a = 126 - 90

6a = 36

a = 36/6

a = 6

Therefore, the original number of sixes is 6

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