Question

What are the zeros of the function? f(x)=x^2+7x-60

Answer 1

Answer:

(-12, 0) and (5, 0)

Step-by-step explanation:

f(x) = x² + 7x − 60

Here, a = 1, b = 7, c = -60.  Using the AC method, we need to find factors of a×c that add up to b.

12 × -5 = -60

12 + -5 = 7

The factors are 12 and -5.

f(x) = (x + 12) (x − 5)

The zeros are:

x + 12 = 0, x − 5 = 0

x = -12, x = 5

The zeros are (-12, 0) and (5, 0).

Answer 2

$x^2+7x-60 =0\\x^2-5x+12x-60=0\\x(x-5)+12(x-5)=0\\(x+12)(x-5)=0\\x=-12 \vee x=5$