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Veronika [31]
3 years ago
10

What is the length, in centimeters, of the hypotenuse of a right triangle with legs measuring V2 cm and 3 cm?​

Mathematics
1 answer:
WINSTONCH [101]3 years ago
5 0

Answer:

\sqrt{13}

Step-by-step explanation:

A is the hyp. And b/c are the sides

A²=b²+c²=3²+2²=9+4=13

Now take the square root of 13 as the answer

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A group of mountain climbers begin an expedition with 250 pounds of food. They plan to eat a total of 12 pounds of food per day.
Advocard [28]
Use the equation y=mx+b where m is the slope (how much it increases each time) and b is the y intercept (starting point).

Your equation would be: y=12x+0 because they eat 12 pounds each day and they start out having eaten 0 pounds.

To solve the equation, plug in the total amount of food for y and use algebra to solve for x:
250=12x
(divide by 12)
(250/12)=x
X=20.833

Their food would last approximately 20 days. (Make sure you round if required)

6 0
3 years ago
Winston has $200. He spends 20% of his money on a pair of shoes. how much money did he spend on the pairs of shoes?
masha68 [24]

Answer:

$40

Step-by-step explanation:

200 - 20% = 160

200 - 160 = 40

3 0
2 years ago
Select all of the terms that apply to the shape.
Leokris [45]

Hexagon is the answer o the shape

4 0
3 years ago
Read 2 more answers
Clase, ¿cuánto es 2.000 − 502?
coldgirl [10]

Answer:

1498  or Mil cuatrocientos noventa y ocho (Espanol)

Step-by-step explanation:

2,000 - 502 = 2,000 - 500 - 2.

2,000 - 500 = 1500

1500 - 2 = 1498

6 0
3 years ago
The function H(t) = −16t2 + 60t + 95 shows the height H(t), in feet, of a projectile after t seconds. A second object moves in t
EleoNora [17]
H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t

h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79

g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8

Between 2 and 3 seconds. 
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1

h(t) = g(t) ⇒ 131 = 131

<span>It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up. </span>
5 0
4 years ago
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