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kvasek [131]
1 year ago
6

A ball is dropped from a height of 400 feet. Each time it hits the ground,it reaches a height that is three-fiths its previous h

eight.Which formula represents the height of the ball after each bounce.

Mathematics
1 answer:
weqwewe [10]1 year ago
6 0

The linear equation 400(3/5)^n-1 represent and satisfy the conditions which is given in the statement. Thus option A is a correct option.

According to the statement

We have to find that the which equation represent the all given conditions in the statement.

So, For this purpose, we know that the

A linear equation is an equation in which the highest power of the variable is always 1.

The given information is:

A ball is dropped from a height of 400 feet. Each time it hits the ground,it reaches a height that is three-fifths its previous height.

From this statement, it is clear that the height of ball decreases to the three-fifth of the original height before touching the ground.

there is decrease in the height.

Hence the equation 400(3/5)^n-1 represent and satisfy the decrease of the height of the ball.

So, The linear equation 400(3/5)^n-1 represent and satisfy the conditions which is given in the statement. Thus option A is a correct option.

Learn more about linear equation here

brainly.com/question/4074386

#SPJ1

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Sean tossed a coin off a bridge into the stream below. The path of the coin can be represented by the equation 2 h tt = − 16t^2+
tekilochka [14]

Answer:

It will take 5.61 seconds for the coin to reach the stream.

Step-by-step explanation:

The height of the coin, after t seconds, is given by the following equation:

h(t) = -16t^{2} + 72t + 100

How long will it take the coin to reach the stream?

The stream is the ground level.

So the coin reaches the stream when h(t) = 0.

h(t) = -16t^{2} + 72t + 100

-16t^{2} + 72t + 100 = 0

Multiplying by (-1)

16t^{2} - 72t - 100 = 0

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

16t^{2} - 72t - 100 = 0

So

a = 16, b = -72, c = -100

\bigtriangleup = (-72)^{2} - 4*16*(-100) = 11584

t_{1} = \frac{-(-72) + \sqrt{11584}}{2*16} = 5.61

t_{2} = \frac{-(-72) - \sqrt{11584}}{2*16} = -1.11

Time is a positive measure, so we take the positive value.

It will take 5.61 seconds for the coin to reach the stream.

3 0
3 years ago
HELP!!! It’s due is 20 minutes
Zinaida [17]

Answer:

B

Step-by-step explanation:

33.8 Rounded

Use Pythagorean theorem :)

Brainliest?

4 0
3 years ago
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A satellite cable company charges an installation fee of $50 plus an additional $35.95 per month for service.
wolverine [178]
My answer would be 85.95
3 0
3 years ago
♦♦Will mark brainliest♦♦
Blababa [14]
I think the answer is 8.5 h
8 0
3 years ago
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It’s a review please HELP ASAP I’ve been stuck on it for awhile now
AlladinOne [14]
<h3>Answer:   7 goes in the blank space</h3>

The range of values for x is 2 < x < 7

========================================

Explanation:

The hinge theorem says that the larger the opposite side is, the larger the angle will be.

AD = 11, DC = 8

Since AD > DC, this means angle ABD > angle DBC.

--------

angle ABD > angle DBC

20 > 4x-8

20+8 > 4x-8+8 ... add 8 to both sides

28 > 4x

4x < 28 ... flip both sides and the inequality sign

4x/4 < 28/4 ... divide both sides by 4

x < 7

--------

At the same time, the angle 4x-8 cannot be 0 or negative.

So we say 4x-8 > 0. Let's solve this for x.

4x-8 > 0

4x-8+8 > 0+8 ... add 8 to both sides

4x > 8

4x/4 > 8/4 ... divide both sides by 4

x > 2

2 < x ... flip both sides and the inequality sign

--------

We have 2 < x and x < 7. Both of these combine to the compound inequality 2 < x < 7

We can pick any value between 2 and 7 as long as we dont pick x = 2 or we dont pick x = 7.

6 0
3 years ago
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