Answer:
the probability is 2/9
Step-by-step explanation:
Assuming the coins are randomly selected, the probability of pulling a dime first is the number of dimes (4) divided by the total number of coins (10).
p(dime first) = 4/10 = 2/5
Then, having drawn a dime, there are 9 coins left, of which 5 are nickels. The probability of randomly choosing a nickel is 5/9.
The joint probability of these two events occurring sequentially is the product of their probabilities:
p(dime then nickel) = (2/5)×(5/9) = 2/9
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<em>Alternate solution</em>
You can go at this another way. You can list all the pairs of coins that can be drawn. There are 90 of them: 10 first coins and, for each of those, 9 coins that can be chosen second. Of these 90 possibilities, there are 4 dimes that can be chosen first, and 5 nickels that can be chosen second, for a total of 20 possible dime-nickel choices out of the 90 total possible outcomes.
p(dime/nickel) = 20/90 = 2/9
Do long division but the answer is 2/7 or 0.2857
Answer:
3/5
Step-by-step explanation:
7/15 + 2/15 = 9/15
both 9 nad 15 are divisible by 3
9/15 = 3/5
The correct answer is B. cm3
This is saying "centimeters cubed", and is true because you are multiplying 3 dimensions of centimeters, width*length*height, to get the answer. Thus, you are multiplying the numbers <em>and </em>the units. 30*30*25 and cm*cm*cm
to have 2.40$ between 30 dimes and nickels she would have to have 18 dimes being 1.80$ and 12 nickles being .60 cents.