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3 years ago

1/2+4/9 less than 1 or greater than 1

Mathematics

2 answers:

SVEN [57.7K]3 years ago

8 0

Answer: 17/18

Step-by-step explanation:

It would be less than 1 because it doesn’t have a a one in front of the fraction

Hope this helps :)

Nadya [2.5K]3 years ago

5 0

Answer: It is greater than 1.

Step-by-step explanation:

First you have to multiply the numerator of the first fraction with the denominator of the second fraction, it gives you 9(1x9). Then, multiply the denominator of the first fraction with the numerator of the second fraction, it gives you 8(4x2). After that, multiply the denominator of the first fraction with the denominator of the second fraction, it gives you 18(2x9). Finally sum the first two answers you got, 8 and 9 = 17, and put this number (17) above the 18. So, the fraction will be 17/18 and this is less than 1 cause it would have to be 18/18 to be 1.

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The measurenicnt of the circumference of a circle is found to be 56 centimeters. The possible error in measuring the circumferen

BartSMP [9]

Answer:

(a) Approximate the percent error in computing the area of the circle: 4.5%

(b) Estimate the maximum allowable percent error in measuring the circumference if the error in computing the area cannot exceed 3%: 0.6 cm

Step-by-step explanation:

(a)

First we need to calculate the radius from the circumference:

$c=2\pi r\\r=\frac{c}{2\pi } \\c=8.9 cm$

I leave only one decimal as we need to keep significative figures

Now we proceed to calculate the error for the radius:

$\Delta r=\frac{dt}{dc} \Delta c\\\\\frac{dt}{dc} = \frac{1}{2 \pi } \\\\\Delta r=\frac{1}{2 \pi } (1.2)\\\\\Delta r= 0.2 cm$

$r = 8.9 \pm 0.2 cm$

Again only one decimal because the significative figures

Now that we have the radius, we can calculate the area and the error:

$A=\pi r^{2}\\A=249 cm^{2}$

Then we calculate the error:

$\Delta A= (\frac{dA}{dr} ) \Delta r\\\\\Delta A= 2\pi r \Delta r\\\\\Delta A= 11.2 cm^{2}$

$A=249 \pm 11.2 cm^{2}$

Now we proceed to calculate the percent error:

$\%e =\frac{\Delta A}{A} *100\\\\\%e =\frac{11.2}{249} *100\\\\\%e =4.5\%$

(b)

With the previous values and equations, now we set our error in 3%, so we just go back changing the values:

$\%e =\frac{\Delta A}{A} *100\\\\3\%=\frac{\Delta A}{249} *100\\\\\Delta A =7.5 cm^{2}$

Now we calculate the error for the radius:

$\Delta r= \frac{\Delta A}{2 \pi r}\\\\\Delta r= \frac{7.5}{2 \pi 8.9}\\\\\Delta r= 0.1 cm$

Now we proceed with the error for the circumference:

$\Delta c= \frac{\Delta r}{\frac{1}{2\pi }} = 2\pi \Delta r\\\\\Delta c= 2\pi 0.1\\\\\Delta c= 0.6 cm$

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3 years ago

Tori worked 48 hours one week. Her hourly pay for 40 hours is $16.20. Her overtime rate is 1.5. What was her

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Her total pay that week was $660

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2 years ago

The two-way table shows the number of books of each type in Eliza's home what is the probability that a randomly selected refer

Salsk061 [2.6K]

Answer:

B. 0.4

Step-by-step explanation:

Use the definition of the probability

$Pr=\dfrac{\text{Number of all favorable outcomes}}{\text{Number of all possible outcomes}}$

You have to find the probability that a randomly selected reference book is hard cover. Hence, from the table

Number of all possible outcomes = Number of Reference books = 25
Number of all favorable outcomes = Number of Hardcover Reference books = 10

So, the probability is

$Pr=\dfrac{10}{25}=\dfrac{40}{100}=0.4$

6 0

3 years ago

Read 2 more answers

Please help with this problem?!?

STALIN [3.7K]

Answer:

37.5%

Step-by-step explanation:

3/8=37.5%

Hope this helps! :)

4 0

3 years ago

Read 2 more answers

Y = 4x+1 y=x^2 + 2x - 2 A.6,2 B. 2,6 C. -6,2 D. -6,-2

natta225 [31]

Answer:

The solution is (3,13) and (-1,-3). So none of the mentioned options is correct.

Step-by-step explanation:

Given that

$y = 4x + 1 (i)$

$y = x^2 + 2x -2 (ii)$

Now, by susbstituting the value of 'y' from equation i to equation ii, we get

$4x+1=x^2 + 2x -2$

$0=x^2 + 2x -2-4x-1$

$0=x^2 + (2x -4x) +(-2-1)$

$0=x^2 + (-2x) +(-3)$

$0=x^2 -2x -3$

$x^2 -2x -3 = 0 (iii)$

Now by factorization, equation iii can be written as

$x^2 -3x +x -3 = 0$

$x(x -3) + 1(x -3) = 0$

$(x -3)(x +1) = 0$

x = 3 and x = -1

By putting the values of x in equation i, we get

y = 4(3) + 1

y = 12 +1

y = 13

and

y = 4(-1) + 1

y = -4 +1

y = -3

Therefore, the solution is (3,13) and (-1,-3). So none of the mentioned options is correct.

7 0

3 years ago