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3 years ago

Someone please help me ASAP!

Mathematics

2 answers:

loris [4]3 years ago

8 0

It would be (-5,-1) yw

Free_Kalibri [48]3 years ago

6 0

Answer:

(-7,-1)

Step-by-step explanation:

bcoz coordinates of a is (-6,-2) and x=-6 we use the x-1 to find the new x which is

-6-1=-7

and to find y you should use y-3 and replace y with 2 which will be

2-3=-1

and y =-1

so the new coordinates are -7 for x-axis and -1for y-axis

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A random variable X with a probability density function () = {^-x > 0

Sliva [168]

The solutions to the questions are

The probability that X is between 2 and 4 is 0.314
The probability that X exceeds 3 is 0.199
The expected value of X is 2
The variance of X is 2

<h3>Find the probability that X is between 2 and 4</h3>

The probability density function is given as:

f(x)= xe^ -x for x>0

The probability is represented as:

$P(x) = \int\limits^a_b {f(x) \, dx$

So, we have:

$P(2 < x < 4) = \int\limits^4_2 {xe^{-x} \, dx$

Using an integral calculator, we have:

$P(2 < x < 4) =-(x + 1)e^{-x} |\limits^4_2$

Expand the expression

$P(2 < x < 4) =-(4 + 1)e^{-4} +(2 + 1)e^{-2}$

Evaluate the expressions

P(2 < x < 4) =-0.092 +0.406

Evaluate the sum

P(2 < x < 4) = 0.314

Hence, the probability that X is between 2 and 4 is 0.314

<h3>Find the probability that the value of X exceeds 3</h3>

This is represented as:

$P(x > 3) = \int\limits^{\infty}_3 {xe^{-x} \, dx$

Using an integral calculator, we have:

$P(x > 3) =-(x + 1)e^{-x} |\limits^{\infty}_3$

Expand the expression

$P(x > 3) =-(\infty + 1)e^{-\infty}+(3+ 1)e^{-3}$

Evaluate the expressions

P(x > 3) =0 + 0.199

Evaluate the sum

P(x > 3) = 0.199

Hence, the probability that X exceeds 3 is 0.199

<h3>Find the expected value of X</h3>

This is calculated as:

$E(x) = \int\limits^a_b {x * f(x) \, dx$

So, we have:

$E(x) = \int\limits^{\infty}_0 {x * xe^{-x} \, dx$

This gives

$E(x) = \int\limits^{\infty}_0 {x^2e^{-x} \, dx$

Using an integral calculator, we have:

$E(x) = -(x^2+2x+2)e^{-x}|\limits^{\infty}_0$

Expand the expression

$E(x) = -(\infty^2+2(\infty)+2)e^{-\infty} +(0^2+2(0)+2)e^{0}$

Evaluate the expressions

E(x) = 0 + 2

Evaluate

E(x) = 2

Hence, the expected value of X is 2

<h3>Find the Variance of X</h3>

This is calculated as:

V(x) = E(x^2) - (E(x))^2

Where:

$E(x^2) = \int\limits^{\infty}_0 {x^2 * xe^{-x} \, dx$

This gives

$E(x^2) = \int\limits^{\infty}_0 {x^3e^{-x} \, dx$

Using an integral calculator, we have:

$E(x^2) = -(x^3+3x^2 +6x+6)e^{-x}|\limits^{\infty}_0$

Expand the expression

$E(x^2) = -((\infty)^3+3(\infty)^2 +6(\infty)+6)e^{-\infty} +((0)^3+3(0)^2 +6(0)+6)e^{0}$

Evaluate the expressions

E(x^2) = -0 + 6

This gives

E(x^2) = 6

Recall that:

V(x) = E(x^2) - (E(x))^2

So, we have:

V(x) = 6 - 2^2

Evaluate

V(x) = 2

Hence, the variance of X is 2

Read more about probability density function at:

brainly.com/question/15318348

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<u>Complete question</u>

A random variable X with a probability density function f(x)= xe^ -x for x>0\\ 0& else

a. Find the probability that X is between 2 and 4

b. Find the probability that the value of X exceeds 3

c. Find the expected value of X

d. Find the Variance of X

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2 years ago

Given that R=9x+8y find x when y=8 and R=4

Ilya [14]

Answer:

Step-by-step explanation:

R = 9x + 8y

4 = 9x + 8*8

4 = 9x + 64

Subtract 64 from both sides

4 - 64 = 9x + 64 - 64

-60 = 9x

Divide both sides by 9

-60/9 = 9x/9

-20/3 = x

x = -6 2/3

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3 years ago

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UNO [17]

Answer:

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Step-by-step explanation:

An inverse of a function is one that reverses the operation of the function such that the result of the function on a variable, is reversed back to the initial variable

Therefore, when we have the the result of the function, f on x as y given as follows;

f(x) = y

The inverse of the function, g on the result, y gives the initial variable, x as follows;

g(y) = x

Example of invertible functions includes;

f(x) = x²

An example of a non-invertible function includes;

f(x) = 2·x².

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3 years ago

What is the slope of the line below? If necessary, enter your answer as a

alisha [4.7K]

Step-by-step explanation:

Use formula to find the slope/gradient

$\frac{y2 - y1}{x2 - x1}$

(-5, -1) = (x1, y1)

(5, 11) = (x2, y2)

So,

$= \frac{11 - ( - 1)}{5 - ( - 5)} \\ = \frac{12}{10 } \\ = \frac{6}{5}$

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3 years ago

The test scores of students in a math class are 46, 40, 50, 43, 35, 41, 50, 42, 38, and 48. What is the mean of this set of data

zimovet [89]

Mean is the average. You would add up all the numbers and divide by how many numbers you have. 433/10=43.3

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