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2 years ago

Sue has 3 apples. Jim has 4 oranges. Which child has an even number of items?

Mathematics

1 answer:

storchak [24]2 years ago

4 0

Answer:

Jim has an even number of items [or more specifically four fruits].

Step-by-step explanation:

First: Ask yourself the question: what is even?

An even number is 2 and every multiple of 2. So, every other number is not an even number; they're odd.

That makes things easier, right?

Second: Evaluate who has an even number of items:

Sue has 3 apples. So she has 3 items. Is three a multiple of 2?

2: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20

Three is not listed in this list so it's not a even number. It would have appeared between two and four. So, three is odd.

Jim has 4 oranges. So he has 4 items. Is four a multiple of 2?

2: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20

4 is a multiple of 2. So it is an even number. So Jim has an even number of items [or fruits].

Thanks

Topic: Number Features

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Answer:

The area of the new rectangle is 882 in².

Step-by-step explanation:

Let l be the length and w be the width of the original rectangle,

So, the area of the original rectangle is,

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Given, A = 72 in²,

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And, new width = 3.5 w,

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Solve for m:
2 m - 5 - 3 = 10 - m

Subtract like terms. -3 - 5 = -8:
2 m - 8 = 10 - m

Add m to both sides:
2 m + m - 8 = (m - m) + 10

m - m = 0:
2 m + m - 8 = 10

2 m + m = 3 m:
3 m - 8 = 10

Add 8 to both sides:
3 m + (8 - 8) = 8 + 10

8 - 8 = 0:
3 m = 10 + 8

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Divide both sides of 3 m = 18 by 3:
(3 m)/3 = 18/3

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