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kakasveta [241]
3 years ago
13

Find the zeros of the function.9x^2-36=0I've gotten half way right up to9(x^2-4)=0​

Mathematics
1 answer:
Airida [17]3 years ago
7 0

Answer:

x = ±2

Step-by-step explanation:

9x^2-36=0

Using the square root property

9x^2 = 36

Divide each side by 9

x^2 = 4

Take the square root of each side

sqrt(x^2) = sqrt(4)

x = ±2

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Ahorras $15 por semana para comprar una de las bicicletas mostradas.
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Answer:

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Step-by-step explanation:

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7 0
3 years ago
What is the next step in this construction?
bezimeni [28]

<u>Answer:</u>

The correct answer option is B. Construct a line perpendicular to XP through point A.

<u>Step-by-step explanation:</u>

We are given an incomplete figure of construction of a perpendicular line and we are to determine whether which of the given answer options is the next step in the construction.

From the given marks, we can deduce that a perpendicular line to XY is being constructed, passing through P.

So the next step must be to construct a line perpendicular to XP through point A to complete the construction.

8 0
3 years ago
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3x(x2 + 2x – 6) + 4(x2<br> – 6x + 2)
Drupady [299]

Step-by-step explanation:

3x(x2 + 2x – 6) + 4(x2

– 6x + 2)

4 0
3 years ago
1.
Eddi Din [679]

Answer:

a) y=\dfrac{5}{2}x

b) yes the two lines are perpendicular

c) y=\dfrac{5}{4}x+6

Step-by-step explanation:

a) All this is asking if to find a line that is perpendicular to 2x + 5y = 7 AND passes through the origin.

so first we'll find the gradient(or slope) of 2x + 5y = 7, this can be done by simply rearranging this equation to the form y = mx + c

5y = 7 - 2x

y = \dfrac{7 - 2x}{5}

y = \dfrac{7}{5} - \dfrac{2}{5}x

y = -\dfrac{2}{5}x+\dfrac{7}{5}

this is changed into the y = mx + c, and we easily see that -2/5 is in the place of m, hence m = \frac{-2}{5} is the slope of the line 2x + 5y = 7.

Now, we need to find the slope of its perpendicular. We'll use:

m_1m_2=-1.

here both slopesm_1 and m_2 are slopes that are perpendicular to each other, so by plugging the value -2/5 we'll find its perpendicular!

\dfrac{-2}{5}m_2=-1.

m_2=\dfrac{5}{2}.

Finally, we can find the equation of the line of the perpendicular using:

(y-y_1)=m(x-x_1)

we know that the line passes through origin(0,0) and its slope is 5/2

(y-0)=\dfrac{5}{2}(x-0)

y=\dfrac{5}{2}x is the equation of the the line!

b) For this we need to find the slopes of both lines and see whether their product equals -1?

mathematically, we need to see whether m_1m_2=-1 ?

the slopes can be easily found through rearranging both equations to y=mx+c

Line:1

2x + 3y =6

y =\dfrac{-2x+6}{3}

y =\dfrac{-2}{3}x+2

Line:2

y = \dfrac{3}{2}x + 4

this equation is already in the form we need.

the slopes of both equations are

m_1 = \dfrac{-2}{3} and m_2 = \dfrac{3}{2}

using

m_1m_2=-1

\dfrac{-2}{3} \times \dfrac{3}{2}=-1

-1=-1

since the product does equal -1, the two lines are indeed perpendicular!

c)if two perpendicular lines have the same intercept, that also means that the two lines meet at that intercept.

we can easily find the slope of the given line, y = − 4 / 5 x + 6 to be m=\dfrac{-4}{5} and the y-intercept is c=6 the coordinate at the y-intercept will be (0,6) since this point only lies in the y-axis.

we'll first find the slope of the perpendicular using:

m_1m_2=-1

\dfrac{-4}{5}m_2=-1

m_2=\dfrac{5}{4}

we have all the ingredients to find the equation of the line now. i.e (0,6) and m

(y-y_1)=m(x-x_1)

(y-6)=\dfrac{5}{4}(x-0)

y=\dfrac{5}{4}x+6

this is the equation of the second line.

side note:

this could also have been done by simply replacing the slope(m1) of the y = − 4 / 5 x + 6 by the slope of the perpendicular(m2): y = 5 / 4 x + 6

8 0
3 years ago
Slope = -2/5 y-intercept= 0
densk [106]

Answer:

y=(-2/5)x

Step-by-step explanation:

Assuming that the goal is to find the linear equation in slope-intercept form, this problem is pretty simple.

Slope intercept form is y=mx+b, where m is the slope and b is the y-intercept. We just have to plug in the information

y=(-2/5)x+0

Simplifies to:

y=(-2/5)x

3 0
3 years ago
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