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kakasveta [241]
3 years ago
13

Find the zeros of the function.9x^2-36=0I've gotten half way right up to9(x^2-4)=0​

Mathematics
1 answer:
Airida [17]3 years ago
7 0

Answer:

x = ±2

Step-by-step explanation:

9x^2-36=0

Using the square root property

9x^2 = 36

Divide each side by 9

x^2 = 4

Take the square root of each side

sqrt(x^2) = sqrt(4)

x = ±2

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Step-by-step explanation:

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First, expand 3(x-2), which will obtain 3x-6.

Next, expand (1/2)(6x-2), which gives 3x - 1.

The result at this point should be as shown below:

3x  - 6 + 7x = 3x - 1

Now, we would shift all x terms to the left and all number terms to the right.

3x + 7x - 3x =  - 1 + 6

After simplifying, the final equation would be:

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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Galina-37 [17]

Answer:

.7

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2 years ago
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Write an equation of lines whose graph is parallel to the graph of y=3x-10
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7 0
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Yanka [14]

Answer:

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Step-by-step explanation:

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