Find the zeros of the function.9x^2-36=0I've gotten half way right up to9(x^2-4)=0
1 answer:
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Note: Actually, the division problem should be in reverse order. It should be given as ---------(i)
But according to the given problem (x + 1) / (x² + 3 x + 2).
Here, (x² + 3 x + 2) > (x + 1)
or, (x + 2) > 1
Concept: By using the property of division, if the numerator is less than the denominator then the quotient will always be 0 (zero)
Therefore the option (d) 0 will be the correct option.