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3 years ago

How do I solve this problem if x mean the missing number? 16\3 = 12\x

1 answer:

3 0

Set this up as a fraction, then cross multiply and solve. In our case, cross multiplying will get us 16x=36, which gets us x=9/4.

:)

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DOES ANYONE KNOW THIS?????

dedylja [7]

Answer:

if i;m right its 45 degrees

Step-by-step explanation:

5 0

3 years ago

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The price of gold rose from $790 per ounce to $860 per ounce what percent increase does this amount represent round to the neare

neonofarm [45]

There’s so many number

8 0

3 years ago

Now, use your research to decide which business is the best choice for this community. Explain your choice in two to three sente

MA_775_DIABLO [31]

Answer:

The business which offers services needed by the citizens of the community, and which is most profitable. That is the best business.

Step-by-step explanation:

You didn't state which community you are referring to. However, the business that is best for any community is a business which offers services mostly needed by the citizens of the community, and which is most profitable.

9 0

3 years ago

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Elena and Jada are 25 miles apart when they start moving toward each other. Elena runs at a constant speed of 6 mph and Jada wal

Setler [38]

<u>Answer:</u>

The Time taken by Elena and Jade to meet up is 2.5 hours

<u>Explanation:</u>

Given,

Elena moves with a speed of 6mph while Jada walks at a speed of 4 mph

Also, Distance can be calculated by the formula

$Distance = Speed * Time$

To find out the Total speed, i.e., speed of both Elena and Jada as both of them are walking in opposite direction we should add the speed of both the persons, if in same direction we should subtract the values

Here it will be: $6 + 4$ = 10mph

Distance apart is given as 25 miles. Substituting the values,

$Distance = Speed * Time$

25 = $10 * time$

Time = 25/10

Time = 2.5 hour

Hence, It will take 2.5 hours to meet up.

3 0

3 years ago

Consider the following region R and the vector field F. a. Compute the two-dimensional curl of the vector field. b. Evaluate bo

Shalnov [3]

Looks like we're given

$\vec F(x,y)=\langle-x,-y\rangle$

which in three dimensions could be expressed as

$\vec F(x,y)=\langle-x,-y,0\rangle$

and this has curl

$\mathrm{curl}\vec F=\langle0_y-(-y)_z,-(0_x-(-x)_z),(-y)_x-(-x)_y\rangle=\langle0,0,0\rangle$

which confirms the two-dimensional curl is 0.

It also looks like the region $R$ is the disk $x^2+y^2\le5$ . Green's theorem says the integral of $\vec F$ along the boundary of $R$ is equal to the integral of the two-dimensional curl of $\vec F$ over the interior of $R$ :

$\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\iint_R\mathrm{curl}\vec F\,\mathrm dA$

which we know to be 0, since the curl itself is 0. To verify this, we can parameterize the boundary of $R$ by

$\vec r(t)=\langle\sqrt5\cos t,\sqrt5\sin t\rangle\implies\vec r'(t)=\langle-\sqrt5\sin t,\sqrt5\cos t\rangle$

$\implies\mathrm d\vec r=\vec r'(t)\,\mathrm dt=\sqrt5\langle-\sin t,\cos t\rangle\,\mathrm dt$

with $0\le t\le2\pi$ . Then

$\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\int_0^{2\pi}\langle-\sqrt5\cos t,-\sqrt5\sin t\rangle\cdot\langle-\sqrt5\sin t,\sqrt5\cos t\rangle\,\mathrm dt$

$=\displaystyle5\int_0^{2\pi}(\sin t\cos t-\sin t\cos t)\,\mathrm dt=0$

7 0

3 years ago