Hello,
r=5(1+cos t)
r'=5(-sin t)
r²+r'²= 25[(1+cos t)²+(-sin t)²]=50(1-cos t)=50 sin² (t/2)
Between 0 and π, sin x>0 ==>|sin x|=sin x
![l= 2*5* \int\limits^{\pi}_0{sin( \frac{t}{2} )} \, dt= 5[-cos (t/2)]_0^{\pi}\\\\ =5(0+1)=5](https://tex.z-dn.net/?f=l%3D%202%2A5%2A%20%5Cint%5Climits%5E%7B%5Cpi%7D_0%7Bsin%28%20%5Cfrac%7Bt%7D%7B2%7D%20%29%7D%20%5C%2C%20dt%3D%205%5B-cos%20%28t%2F2%29%5D_0%5E%7B%5Cpi%7D%5C%5C%5C%5C%0A%3D5%280%2B1%29%3D5)
Here is the method but i may have make some mistakes.
Answer:
#8 might be y= -3x + 5
Step-by-step explanation:
This may help
100 and 101
the two integers are n and n+1. this means that 2n+1=201. n=100 and n+1=101
Exact Form: 55/8
Decimal: 6.875
Mixed Number: 6 7/8
First, write it as an equation
2.50+3x=5.05
Next, subtract 2.50 from both sides
2.50-2.50+3x=5.05-2.50
3x=2.55
Divide 3 on both sides
3x/3=2.55/3
x=0.85
The cost of a bag of chips is 0.85
hope i helped :D