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Lesechka [4]
3 years ago
10

Help me!! grade due tonight :(

Mathematics
1 answer:
Grace [21]3 years ago
8 0
It’s c. hope this helps!
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How many ounces in all
Shalnov [3]

Answer:

35+8=43 ounnces

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The graph of y = f(x) has a maximum point at (-2, 4).
solmaris [256]

Answer:

(2,4).

Step-by-step explanation:

Graph of y = f(-x).

The values of x in f(-x) assume the values of -x in f(x).

For example, f(-2) in f(x) is f(2) in f(-x), and f(2) in f(x) is f(-2) in f(-x).

b) Write down the coordinates of the maximum point of the graph of y = f(-x).

In f(x), we have that x = -2. So in f(-x), it will be x = 2. y remains unchanged. So

(2,4).

5 0
3 years ago
What can you say about the Y values are the two functions??? Help please !!!!
velikii [3]

Answer:

D. The minimum y-value of g(x) approaches -3

Step-by-step explanation:

Form a table for values of x with corresponding values for f(x) and g(x)

<u>x   </u>                 <u>f(x)=3x²-3                                         g(x)=2^x -3                           </u>

-3                   =3(-3²)-3=24                                       2⁻³ -3 = -2.88

-2                    =3(-2²)-3=9                                        2⁻² -3 = -2.75

-1                     =3(-1²)-3=0                                         2⁻¹-3 = -2.5

0                      =3(0²)-3= -3                                        2⁰ -3 = -2

1                       =3(1²)-3=0                                           2¹ -3 = -1

2                      =3(2²)-3=9                                          2²- 3 = 1

3                     =3(3²)-3=24                                          2³ -3= 5

From the table above, you can see the minimum value of y in g(x)  -2.88 approaches -3

7 0
2 years ago
What value is equivalent to 30 − 2^3 × 3?
wlad13 [49]
30
−
(
2
3
)
(
x
3
)
=
30
+
−
8
x
3


=
−
8
x
3
+
30
3 0
3 years ago
What is the equation of a circle with its center at (0,-2) and passing through the point (3,-5)
Ksivusya [100]
Circle's Standard Form Equation:
r^{2} = (x - xo)^{2} + (y - yo)^{2}

First you need to substitute the C (0,-2) in the equation, where: Xo = 0 and Yo = -2;

r^{2} = (x - 0)^{2} + (y - ( -2))^{2} \\ r^{2} = x^{2} + (y + 2)^{2}

Now you substitute the Point (3,-5) values in the last expression, where: X = 3 and Y = -5;

r^{2} = 3^{2} + (( - 5) + 2)^{2} \\ r ^{2} = 9 + ( - 3)^{2} \\ r^{2} = 9 + 9 \\ {r}^{2} = 18

Now you get the R^2 value and substitute in the equation that you found putting the C values on it:

r^{2} = x^{2} + (y + 2)^{2} \\ x^{2} + (y + 2)^{2} = 18

Here is your standard form equation of the circle.
7 0
3 years ago
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