Recall the ideal gas law:
<em>P V</em> = <em>n R T</em>
where
<em>P</em> = pressure
<em>V</em> = volume
<em>n</em> = number of gas molecules
<em>R</em> = ideal gas constant
<em>T</em> = temperature
If both <em>n</em> and <em>T</em> are fixed, then <em>n R T</em> is a constant quantity, so for two pressure-volume pairs (<em>P</em>₁, <em>V</em>₁) and (<em>P</em>₂, <em>V</em>₂), you have
<em>P</em>₁ <em>V</em>₁ = <em>P</em>₂ <em>V</em>₂
(since both are equal to <em>n R T </em>)
Solve for <em>V</em>₂ :
<em>V</em>₂ = <em>P</em>₁ <em>V</em>₁ / <em>P</em>₂ = (104.66 kPa) (525 mL) / (25 kPa) = 2197.86 mL
A) 75/100*X=24 => 3/4*x=24=> X=4*24/3=4*8=32°°°°°°
b) 65/100*X=39 => 13/20*X=39 => X=20*39/13 => X=20*3=60 ~~~~~~ Have a nice day!!!!★★
The answer is b. 38 divided by 10 equals 3.8
Answer:
walang keef fuzzy gasification
