Answer:
<u>Answer</u><u>:</u><u> </u><u>(</u><u>0</u><u>,</u><u> </u><u>-</u><u>4</u><u>)</u><u> </u><u>and</u><u> </u><u>(</u><u>6</u><u>,</u><u> </u><u>1</u><u>)</u>
• x(t) = 6t --- equation (a)
• y(t) = 3t - 2 --- equation (b)
→ From equation (a), make t the subject:

• substitute for t in equation (b)

• Assume t is 1:

• when x is zero, y is -4

• when x is 6, y is 1

Answer: I got 1, 4, and 7
brainlist plz:)
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
Since (-3, -4) is in Quadrant III and the reflected point will be "flipped" vertically the answer is Quadrant II.
7.
(2b^2+7b^2+b)+(2b^2-4b-12)
(9b^2+b)+(2b^2-4b-12)
9b^2+b+2b^2-4b-12
11b^2+b-4b-12
11b^2-3b-12
8.
(7g^3+4g-1)+(2g^2-6g+2)
7g^3+4g-1+2g^2-6g+2
7g^3-2g-1+2g^2+2
7g^3-2g+1+2g^2
7g^3+2g^2-2g+1
Hope this helps!