Answer:
1/ sqrt(1+ln^2(x)) * 1/(ln^2x +1) * 1/x
Step-by-step explanation:
f(x) = sin (tan^-1 (ln(x)))
u substitution
d/du (sin u) * du /dx
cos (u) * du/dx
Let u =(tan^-1 (ln(x))) du/dx =d/dx (tan^-1 (ln(x)))
v substitution
Let v = ln x dv/dx = 1/x
d/dv (tan ^-1 v) dv/dx
1/( v^2+1) * dv/dx
=1/(ln^2x +1) * 1/x
Substituting this back in for du/dx
cos (tan^-1 (ln(x)) * 1/(ln^2x +1) * 1/x
We know that cos (tan^-1 (a)) = 1/ sqrt(1+a^2)
cos (tan^-1 (ln(x)) * 1/(ln^2x +1) * 1/x
1/ sqrt(1+ln^2(x)) * 1/(ln^2x +1) * 1/x
Answer: -60
Step-by-step explanation:
5 - 1/3x = -15
-1/3x = -20
(-3/1)-1/3x=-20(-3/1)
x = -60
Answer:
f^-1(x) = 3 - 5x, second option
Step-by-step explanation:
To determine the inverse simply interchange the variables and solve for y;
f(x) = 3 - x / 5 -> Interchange the variables
x = 3 - y/5 -> Multiply either side by 5
5x = 3 - y -> Subtract three from either side
- y = 5x - 3 -> Divide either side by - 1
y = - 5x + 3
Your solution is f^-1(x) = 3 - 5x
If you would like to know the rate at which she was travelling, you can calculate this using the following steps:300 miles ... 4.5 hoursx miles = ? ... 1 hour300 * 1 = 4.5 * x300 = 4.5 * xx = 300 / 4.5x = 200 / 3x = 66.67 miles per hour Janet was travelling at the rate 66.67 miles per hour.
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