5r=2x=50x+y2 hope this helps
For perpendicular lines, m2 = -1/m1 = -1/(-2/3) = 3/2 [m1 = -2/3]
Required equation is y + 2 = 3/2(x + 2) => y + 2 = 3/2 x + 3 => y = 3/2 x + 1
The GCF of 40 16 and 24 is 8
<h3>How to determine the GCF of 40 16 and 24?</h3>
The numbers are given as:
40 16 and 24
Start by listing out the factors of the numbers:
This is done as follows:
- The factors of 40 are: 1, 2, 4, 5, 8, 10, 20, 40
- The factors of 16 are: 1, 2, 4, 8, 16
- The factors of 24 are: 1, 2, 3, 4, 6, 8, 12, 24
Then the greatest common factor in the above list is 8.
Hence, the GCF of 40 16 and 24 is 8
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5 5 2 2 0
ten thousands thousands hundreds tens ones
Answer:
1. x = 1, y = -3
2. x = 3, y = 4
Step-by-step explanation:
Here, we want to solve the sets of simultaneous equations;
a) -y = 5x-2
-3y = -5x + 14
substitute 1 into ii
3(5x-2) = -5x + 14
15x - 6 = -5x + 14
15x + 5x = 14 + 6
20x = 20
x = 20/20
x = 1
from;
-y = 5x - 2
y = -5x + 2
y = -5(1) + 2
y = -3
b) -2y = -6x + 10
2y = x + 5
Substitute ii into i
-(x + 5) = -6x + 10
-x - 5 = -6x + 10
-x + 6x = 10 + 5
5x = 15
x = 15/5
x = 3
2y = x + 5
2y = 3 + 5
2y = 8
y = 8/2
y = 4