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il63 [147K]
3 years ago
14

Which statement correctly describes the end behavior of f(x)=ax+b, where a and b are positive numbers?

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
7 0

Answer:

The correct option is 2.

Step-by-step explanation:

The given function is

f(x)=ax+b

Where, a and b are positive numbers.

The given function is the slope intercept form of a linear function. Where a is the slope and b is y-intercept.

Since slope is positive therefore function approaches to infinity as x approaches to infinity and function approaches to negative infinity as x approaches to negative infinity.

It is also proved by using limits.

lim_{x\rightarrow \infty}f(x)=lim_{x\rightarrow \infty}(ax+b)

Apply limits.

lim_{x\rightarrow \infty}f(x)=a(\infty)+b=\infty

Similarly,

lim_{x\rightarrow -\infty}f(x)=lim_{x\rightarrow -\infty}(ax+b)

Apply limits.

lim_{x\rightarrow -\infty}f(x)=a(-\infty)+b=-\infty

Therefore option 2 is correct.

f(x)\rightarrow \infty \text{ as }x\rightarrow \infty

f(x)\rightarrow -\infty \text{ as }x\rightarrow -\infty

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While baking, Evan discovered a recipe that required 1/2 cups of walnuts for very 2 1/4 cups of flour. How many cups of walnuts
Furkat [3]
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<span>Simplfied- 4 cups is 1/2 a cups short of double, since the flour is done is quarters, take the 1/4 cup away from the walnuts. </span>
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4 0
4 years ago
Which ordered pair is a solution of the equation (-6 -2) (-3 2) (4 -4) (6 8)
blagie [28]

Answer:

(-3, 2)

Step-by-step explanation:

That is the point in where the lines intersect

7 0
4 years ago
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What are the zeros of the quadratic function f(x) = 6x2 + 12x - 7?<br>​
mina [271]

Answer:

\frac{-6+\sqrt{78} }{6} and \frac{-6-\sqrt{78} }{6}

Step-by-step explanation:

We are asked that what are the zeros of the quadratic function f(x) = 6x² +12x -7.

So, we have to find the roots of the equation, f(x) = 6x² +12x -7 =0 ...... (1)

Since the quadratic function can not be factorized, so we have to apply Sridhar Acharya's formula.

This formula gives if, ax² +bx +c =0, the the two roots of the equation are

\frac{-b+\sqrt{b^{2}-4ac } }{2a} , \frac{-b-\sqrt{b^{2}-4ac } }{2a}

Therefore, in our case 'a' being 6, 'b' being 12 and 'c' being -7, the two roots of the equation (1) will be

\frac{-12+\sqrt{12^{2}-4*6*(-7) } }{2*6},  \frac{-12-\sqrt{12^{2}-4*6*(-7) } }{2*6}

= \frac{-12+\sqrt{312} }{12},\frac{-12-\sqrt{312} }{12}

=\frac{-6+\sqrt{78} }{6} and \frac{-6-\sqrt{78} }{6}

Hence, x= \frac{-6+\sqrt{78} }{6}

and x= \frac{-6-\sqrt{78} }{6}

(Answer)

9 0
4 years ago
Whoever answers correctly can have brainliest<br> but answer asap
monitta

Answer:

4

Step-by-step explanation:

6 × 2/3 = 6/1 × 2/3 = 12/3 = 4

4 0
3 years ago
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