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My name is Ann [436]
3 years ago
14

Ignore the one I filled in Please help tho!

Mathematics
2 answers:
White raven [17]3 years ago
7 0

Answer:

it's the last one

Step-by-step explanation:

Karolina [17]3 years ago
7 0
The answer is the last option listed: 9 1/5
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The rate of depreciation dv / dt of a machine is inversely proportional to the square of t + 1, where v is the value of the mach
lukranit [14]
The solution for this problem is:
dV/dt = r/(t + 1)², V(0) = $500000, V(1) = $500000 - $200000 = $300000 
∫dV = r∫ 1/(t + 1)² dt 
V(t) = -r/(t + 1) + C 
500000 = -r/(0 + 1) + C 
400000 = -r/(1 + 1) + C 
C = 300000, r = -100000 
V(t) = 100000/(t + 1) + 300000 
V(6) = 100000/(6+ 1) + 300000 
V(6) = 14285.7143 + 300000

V(6) = $314285.71
6 0
3 years ago
Plz, help me with this question!
Katarina [22]

Answer:

C. 250 miles

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Please help! Will mark Brainliest!
borishaifa [10]

Answer:

I wasnt able to put my answer to your current question after this so ill put my response here. If the answer was the first box then the other pair would be the third one. If the second box was the answer then the other pair would be the last one. This is a tough one indeed when you forgot how to do this lol. But based from my knowledge I would go with the 2nd and last one.

5 0
3 years ago
Read 2 more answers
A square has a side length of 520<br> meters. What is the perimeter of<br> the square in kilometers?
kicyunya [14]

Answer: 2.08 km

Step-by-step explanation:

Side of Square = 520 m

Perimeter of Square = Side × 4

                                  = 520 × 4

                                  = 2080 m

1000 m = 1km

2080 m = 2080 ÷ 1000

              = 2.08 km

7 0
3 years ago
An = a1 + (n - 1)d
yarga [219]

Answer:

The car will travel 1980 meters in 15 minutes.

Hence, option 'D' is true.

Step-by-step explanation:

Given that a car travels 300 meters in the first minute, so

  • a₁ = 300

Each minute after, the car travels 120 meters. , so the sequence becomes

a₁, a₂, a₃, a₄, a₅, ...

300, 420, 540, 660, 780, ...

An arithmetic sequence has a constant difference 'd' and is defined by  

a_n=a_1+\left(n-1\right)d

computing the differences of all the adjacent terms

20-300=120,\:\quad \:540-420=120,\:\quad \:660-540=120,\:\quad \:780-660=120

The difference between all the adjacent terms is the same and equal to d=120

now, we have

  • a₁ = 300
  • d = 120

so substituting a₁ = 300 and d = 120 in the nth term of the sequence

a_n=a_1+\left(n-1\right)d

a_n=120\left(n-1\right)+300

a_n=120n+180

Thus, the nth term of the sequence is:

a_n=120n+180

<u>Determining the distance the car travels in 15 minutes</u>

As we have already determined the nth term of the sequence such as

a_n=120n+180

now substituting n = 15

a_{15}=120\left(15\right)+180

a_{15}=1800+180

a_{15}=1980

Therefore, the car will travel 1980 meters in 15 minutes.

Hence, option 'D' is true.

6 0
3 years ago
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