Answer:
64 in 2 is it the answers im not shure
P(x) = 2x² - 4xq(x) = x - 3
To find the answer, we plug q(x) into p(x):
p(q(x)) = 2(x - 3)² - 4(x - 3)p(q(x)) = 2(x² - 6x + 9) - 4x + 12p(q(x)) = 2x² - 12x + 18 - 4x + 12p(q(x)) = 2x² - 16x + 30
The third option is correct.
2.50 would be 25% out of 100%
Hello from MrBillDoesMath!
Answer:
All equations have two real roots.
Discussion:
The solutions of the quadratic ax^2 + bx + c = 0 are given by the formula:
x = (-b +\- sqrt(b^2-4ac) ) / (2a)
The key element is the discriminant, D, which equals (b^2-4ac)
For 2) a = 3, b = 4, c = -4, D = 4^2 - 4(3)(-4) = 16 + 48 = 64 > 0 so there are two real solutions
For 4) D = b^2 - 4ac = (-1)^2 - 4(6)(-1) = 1 + 24 = 25 >0 so there are two real solutions
For 6), a = -3, b = 12, c= -11, D = 12^2 - 4(-3)(-11) = 144 - 132 = 12 > 0 so
there are two real solutions
Thank you,
MrB