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3 years ago

Write your answer as a fraction or as a whole or mixed number 4 4/5 times 2 1/5

Mathematics

2 answers:

Volgvan3 years ago

8 0

Answer:

It would be 10 14/25

Step-by-step explanation:

You could use a calculator for this, but that’d be cheating so let me explain.

We make both of our fractions improper first

4 4/5 = 24/5

2 1/5 = 11/5

We won’t need to change the “bottom number“ since they’re already the same, so let’s multiply them now.

24 x 11 = 264

————

5 x 5 = 24

Ten 24s can fit into 264 so our final number is

10 14/25

shutvik [7]3 years ago

3 0

Answer:

10 14/25

Step-by-step explanation:

first convert mixed numbers to improper fractions

4 4/5 =24/5

2 1/5= 11/5

24/5 × 11/5

multiply it and you will get 264/25

you can't change the improper fraction into a whole number because 25 can't go into 264 evenly. So change the improper fraction to a mixed number. To do that see how many times the denominator (25) can go into the numerator (264)

It 25 go in 264 10 times. 25*10= 250

so the whole number is 10 always keep the denominator (25) the same , then subtract 264 from 250

264-250=14

so you answer is 10 14/25

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2 years ago

I need help with this question, if anyone could help ASAP, that would be much appreciated. In the figure below, mROP = 125° Find

Tema [17]

Answer:The measure of the arc RPQ is 205°

Step-by-step explanation:

Given the figure in which

m∠ROP=125°

we have to find the measure of the arc RPQ.

As QP is diameter i.e a straight line therefore

∠1 and ∠2 forms a linear pair hence these angles are supplementary.

By supplementary law

∠1+∠2=180°

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Now we have to find the measure of the arc RPQ i.e

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3 years ago

What is the average rate of change of f over the interval -1 on a separate sheet of paper and upload the work as a photo. Show a

Anarel [89]

Answer:

Average rate of change for the function $f(x)= x^2-x-1$ over the interval -1<x<1 is -1

Step-by-step explanation:

We need to find average rate of change of f over the interval -1 < x < 1

The function given is: $f(x)= x^2-x-1$

The formula used to find average rate of change is:

$Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}$

We have, a = -1 and b = 1

Finding f(b) when b=1

$f(x)=x^2-x-1\\f(1)=(1)^2-(1)-1\\f(1)=1-1-1\\f(1)=-1$

Now, finding f(a), when a= -1

$f(x)=x^2-x-1\\f(-1)=(-1)^2-(-1)-1\\f(1)=1+1-1\\f(-1)=2-1\\f(-1)=1$

Now, putting values and finding average rate of change

$Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}\\Average\:rate\:of\:change=\frac{f(1)-f(-1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-(1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-1}{1+1}\\Average\:rate\:of\:change=\frac{-2}{2}\\Average\:rate\:of\:change=-1$

So, average rate of change for the function $f(x)= x^2-x-1$ over the interval -1<x<1 is -1

4 0

2 years ago

Write your answer as a fraction or as a whole or mixed number 4 4/5 times 2 1/5​

Write your answer as a fraction or as a whole or mixed number 4 4/5 times 2 1/5