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11Alexandr11 [23.1K]
3 years ago
5

Write your answer as a fraction or as a whole or mixed number 4 4/5 times 2 1/5​

Mathematics
2 answers:
Volgvan3 years ago
8 0

Answer:

It would be 10 14/25

Step-by-step explanation:

You could use a calculator for this, but that’d be cheating so let me explain.

<em>We make both of our fractions improper first</em>

4 4/5 = 24/5

2 1/5 = 11/5

<em>We won’t need to change the “bottom number“ since they’re already the same, so let’s multiply them now.</em>

24 x 11 = 264

————

5 x 5 = 24

<em>Ten 24s can fit into 264 so our final number is</em>

10 14/25

shutvik [7]3 years ago
3 0

Answer:

10 14/25

Step-by-step explanation:

first convert mixed numbers to improper fractions

4 4/5 =24/5  

2 1/5= 11/5

24/5 × 11/5

multiply  it and you will get 264/25

you can't change the improper fraction into a whole number because 25 can't go into 264 evenly. So change the improper fraction to a mixed number. To do that see how many times the denominator (25) can go into the numerator (264)

It 25 go in 264 10 times. 25*10= 250

so the whole number is 10 always keep the denominator (25) the same , then subtract 264 from 250

264-250=14

so you answer is 10 14/25

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Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and
zzz [600]

Answer:

\bold{sin(38^\circ)=cos(52^\circ)}

Step-by-step explanation:

Given that \triangle KJL is a right angled triangle.

\angle JKL = 52^\circ\\\angle KLJ = 38^\circ

and

\angle KJL = 90^\circ

Kindly refer to the attached image of \triangle KJL in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given \triangle KJL.

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

sin\theta =\dfrac{Perpendicular}{Hypotenuse}

sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

cos\theta =\dfrac{Base}{Hypotenuse}

cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}....... (2)

By (1) and (2):

sin(38°) \neq cos(38°).

cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL} ...... (3)

Comparing equations (1) and (3):

we get the both are same.

\therefore \bold{sin(38^\circ)=cos(52^\circ)}

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3 years ago
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Nataliya [291]

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Step-by-step explanation:

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- so we can just change this equation around to H = V / π r^2

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hope this helps :)

8 0
1 year ago
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