Let's define variables:
s = original speed
s + 12 = faster speed
The time for the half of the route is:
60 / s
The time for the second half of the route is:
60 / (s + 12)
The equation for the time of the trip is:
60 / s + 60 / (s + 12) + 1/6 = 120 / s
Where,
1/6: held up for 10 minutes (in hours).
Rewriting the equation we have:
6s (60) + s (s + 12) = 60 * 6 (s + 12)
360s + s ^ 2 + 12s = 360s + 4320
s ^ 2 + 12s = 4320
s ^ 2 + 12s - 4320 = 0
We factor the equation:
(s + 72) (s-60) = 0
We take the positive root so that the problem makes physical sense.
s = 60 Km / h
Answer:
The original speed of the train before it was held up is:
s = 60 Km / h
Answer:
5
Step-by-step explanation:
a polynomial has one quadratic factor and 3 linear factors. One of the linear factors has multiplicity two. What is the degree of the polynomial
A polynomial with one quadratic obtains the forms ( ax² +bx +c ) with 3 linear factors.
Suppose the three linear fractions are :
(x- P) (x-Q) (x- R)
∴
The polynomial = ( ax² +bx +c )(x- P) (x-Q) (x- R)
By factorization, the highest degree of the polynomial = 5
Answer:
Gasoline = 10.2 * 3.80= 38.76
Water= 3 * 3.98 = 11.94
Ice- 3 * 1.99 = 5.97
Oranges= 1 * 8.89 = 8.89
Step-by-step explanation:
I don’t understand this brother plzz explain it better