Answer: -7b² + 2b - 8
Step-by-step explanation:
<u>Given expression</u>
3 - b (7b + 2) + 3b - (11 - b)
<u>Expand parentheses and apply the distributive property if necessary</u>
=3 - b · 7b - b · 2 + 3b - 11 + b
=3 - 7b² - 2b + 3b - 11 + b
<u>Combine like terms</u>
=-7b² + (3b - 2b + b) + (3 - 11)
=
Hope this helps!! :)
Please let me know if you have any questions
The game that is used for the scenario above in terms of fair play is using a balloon. Here, the player will hit the balloon.
<h3>What is the scenario under the balloon game?</h3>
The rule of play are:
This is a classic game with simple rules which are:
- Each player to hit the balloon up and it bonce into the air but when one should not allow it to touch the ground.,
- Players would be tied together in twos and they will juggle a lot of balloon and it have to be more than 1 balloon with one of their hands tied to their back.
A scenario of the worksheet game whose expected value is 0 is given below:
Assume that it costs about $1 for a player to play the billon game and as such, if the player hits a balloon, they will be given $3. what can you say. Can you say that it this game is fair or not? and who has the biggest advantage.
Solution
Note that a game is ”fair” if the expected value is said to be 0. When a player is said to hits a balloon, their net profit often increase by $4. So when the player do not hit a balloon, it drops to $1.
(4)(0.313) + (-1)(0.313)
= 0.939 approximately
Thus, the expected value is $0.939 which tells that the game is fair.
Learn more about fair play from
brainly.com/question/24855677
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A + s = 279
s = 2a
a + 2a = 279
3a = 279
a = 279/3
a = 93 <=== adult
s = 2a
s = 2(93)
s = 186 ....students
Answer:
The answer is 0.15
Step-by-step explanation:
Hope this helps!
Answer:
Step-by-step explanation:
The 90th percentile of a normally distributed curve occurs at 1.282 standard deviations. Similarly, the 10th percentile of a normally distributed curve occurs at -1.282 standard deviations.
To find the 
percentile for the television weights, use the formula:
, where 
is the average of the set, 
is some constant relevant to the percentile you're finding, and 
is one standard deviation.
As I mentioned previously, 90th percentile occurs at 1.282 standard deviations. The average of the set and one standard deviation is already given. Substitute 
, 
, and 
:
Therefore, the 90th percentile weight is 5.1282 pounds.
Repeat the process for calculating the 10th percentile weight:
The difference between these two weights is 
.
