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Anton [14]
3 years ago
15

Can you please help me do my math homework I am struggling its due for tomorrow morning

Mathematics
1 answer:
Lyrx [107]3 years ago
5 0

Answer:

Actual pressure = 36.5.

Step-by-step explanation:

x + 0.08x

= 1.08x

1.08x = 39.42

x = 39.42/ 1.08

= 36.5

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20. Solve 4 - 2(b - 6) = 12<br><br>b = 2<br><br>b = 12<br><br>b = -2<br><br>b = -10​
Maurinko [17]

Answer:

<h2>b=2</h2>

Option A is the correct option.

Solution,

4 - 2(b - 6) = 12 \\ or \: 4 - 2b + 12 = 12 \\ or \: 4 + 12 - 2b = 12 \\ or \: 16 - 2b = 12 \\ or \:  - 2b = 12 - 16 \\ or \:  - 2b = -  4 \\ or \: b =  \frac{ - 4}{ - 2}  \\ b = 2

Hope this helps...

Good luck on your assignment..

3 0
3 years ago
Read 2 more answers
Farrah borrowed $155 from her brother. She has already paid back $15. She plans to pay back $35 each month until the debt is pai
kari74 [83]

Answer:

35x = 155-15

It will take 4 months.

Step-by-step explanation:

7 0
3 years ago
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What is the boundary line for the linear inequality 4x + 2y &lt; 18?
Cloud [144]

Answer:

Simplifying

x = 4.5 + -0.5y

Step-by-step explanation:

4 0
3 years ago
A competitive knitter is knitting a circular place mat. The radius of the mat is given by the formula
Ilia_Sergeevich [38]

Answer: A. A'(t)=\frac{4356\pi}{(t+11)^{3}}-\frac{527076\pi}{(t+11)^{5}}

              B. A'(5) = 1.76 cm/s

Step-by-step explanation: <u>Rate</u> <u>of</u> <u>change</u> measures the slope of a curve at a certain instant, therefore, rate is the derivative.

A. Area of a circle is given by

A=\pi.r^{2}

So to find the rate of the area:

\frac{dA}{dt}=\frac{dA}{dr}.\frac{dr}{dt}

\frac{dA}{dr} =2.\pi.r

Using r(t)=3-\frac{363}{(t+11)^{2}}

\frac{dr}{dt}=\frac{726}{(t+11)^{3}}

Then

\frac{dA}{dt}=2.\pi.r.[\frac{726}{(t+11)^{3}}]

\frac{dA}{dt}=2.\pi.[3-\frac{363}{(t+11)^{2}}].\frac{726}{(t+11)^{3}}

Multipying and simplifying:

\frac{dA}{dt}=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}

The rate at which the area is increasing is given by expression A'(t)=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}.

B. At t = 5, rate is:

A'(5)=\frac{4356\pi}{(5+11)^{3}} -\frac{527076\pi}{(5+11)^{5}}

A'(5)=\frac{4356\pi}{4096} -\frac{527076\pi}{1048576}

A'(5)=\frac{2408693760\pi}{4294967296}

A'(5)=1.76268

At 5 seconds, the area is expanded at a rate of 1.76 cm/s.

5 0
2 years ago
7^14 ÷ 7^2<br> I-ready btw
Lyrx [107]

Answer:

7^12

Step-by-step explanation:

7^14

-----------

7^2

When we divide with the same base, we subtract the exponents

7^(14-2)

7^12

5 0
3 years ago
Read 2 more answers
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