Answer:
minimum value of function is 
.
Step-by-step explanation:
Given function represents a parabola.
Now, here coefficient of 
is positive , so the parabola will be facing upwards and thus the function will be having a minimum.
Now, as we know that minimum value of a parabolic function occurs at
x = 
.
Where , b represents the coefficient of x and a represents the coefficient of .
here, a = 2 , b = -6
Thus = 
= 
So, at x = minimum value will occur and which equals
y = 2×
- 
+ 9 = .
Thus , minimum value of function is .
Given that (p - 1/p) = 4, the value of p² + 1/p² is 18. Detail below
<h3>Data obtained from the questio</h3>
- (p - 1/p) = 4
- p² + 1/p² = ?
<h3>How to determine the value of p² + 1/p²</h3>
(p - 1/p) = 4
Square both sides
(p - 1/p)² = (4)²
(p - 1/p)² = 16 ....(1)
Recall
(a - b)² = a² + b² - 2ab
Thus,
(p - 1/p)² = p² + 1/p² - (2 × p × 1/p)
(p - 1/p)² = p² + 1/p² - 2
From equation (1) above,
(p - 1/p)² = 16
Therefore,
p² + 1/p² - 2 = 16
Rearrange
p² + 1/p² = 16 + 2
p² + 1/p² = 18
Thus, the value of p² + 1/p² is 18
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Answer:
w goes to dependent
and t goes to independent
Step-by-step explanation:
<h3>
Answer: C) 6</h3>
====================================================
Explanation:
The weird looking E symbol is the greek uppercase letter sigma. It refers to a sum.
It tells us to add up terms in the form (-1)^n*(3n+2) where n is an integer ranging from n = 1 to n = 4.
------------------
If n = 1, then we have
(-1)^n*(3n+2) = (-1)^1*(3*1+2) = -5
Let A = -5 as we'll use it later.
------------------
If n = 2, then
(-1)^n*(3n+2) = (-1)^2*(3*2+2) = 8
Let B = 8 since we'll use this later as well
------------------
If n = 3, then
(-1)^n*(3n+2) = (-1)^3*(3*3+2) = -11
Let C = -11
-------------------
If n = 4, then
(-1)^n*(3n+2) = (-1)^4*(3*4+2) = 14
Let D = 14.
--------------------
We'll add up the values of A,B,C,D to get the final answer
A+B+C+D = -5+8+(-11)+14 = 6
This means that
Answer:
(
3
x
+
1
)
(
3
x
−
1
)
is the factorised form of the expression
idk if its right so dont come at me and i also think that it didnt paste right.
