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VARVARA [1.3K]
3 years ago
13

How do you get the fully simplified slope-intercept form?​

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
6 0

Answer:

y = 3x - 7

Step-by-step explanation:

Slope-intercept form:

y = mx + b

Where:

y is the y value.

m is the slope.

x is the x value.

And b is the y-intercept.

First, you want to find your slope. To do this, you can either use the slope formula to find the slope, or just count on the picture:

m = rise/run

m = 3/1

m = 3

With the slope formula, you first need to choose two points.

I chose:

(2, -1) and (3, 2)

Slope formula:

m = (y2 - y1) / (x2 - x1) {It doesn't matter which point you choose to be x2 and x1, just be consistent when you plug it into the formula}

m = (2 - (-1)) / (3 - 2)

m = 3/1

m = 3

Now that you have your slope, all you need is your y-intercept. To find your y-intercept, you can either look at the graph (again) to see where the line intersects with the y-axis, or you can solve it algebraically:

y-int = -7

To solve algebraically, choose a random point on the line and plug it into what you have for your equation so far and then solve for b.

I chose:

(2, -1)

y = 3x + b

-1 = 3(2) + b

-1 = 6 + b

-1 - 6 = b

b = -7

Now you have your final answer:

y = 3x - 7

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Answer:

By AA

ΔWXY ~ΔWVZ

Step-by-step explanation:

Here WXY is an isosceles triangle with legs WX & WY

So WX = WY

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In triangle WVZ

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Find the values of x and y for which the lines are parallel.
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The answer:  " x = 68, y = 72 " .
____________________________
Explanation:
________________________________________
46 + (x - 3) + (y - 3) = 180 .

46 + 1(x - 3) + 1(y-3) = 180 .

46 + 1x - 3 + 1y - 3 = 180 .

46 - 3 - 3 + 1x + 1y = 180 .

40 + x + y = 180 ;

Subtract "40" from EACH SIDE of the equation:
______________________________________
 40 + x + y - 40 = 180 - 40 ;

 to get:

x + y = 140 ;
_____________________________________
Now:
_____________________________________
65 = (x - 3) ;


↔  x - 3 = 65 ;

Add "3" to EACH SIDE of the equation;

    x - 3 + 3 = 65 + 3 ;

to get:
 
           x = 68 .
______________________________
Now:

Since:  "x + y = 140" ;

Let us plug in our known value, "68" ;  for "x" ;

to solve for "y" ;
__________________________________
   x + y = 140 ;
 
  68 + y = 140 ;

↔ y + 68 = 140 ;

Subtract "68" from EACH SIDE of the equation; to isolate "y" on one side of the equation; and to solve for "y" ;
______________________________________________
   y + 68 - 68 = 140 = 68 ;

                  y = 72 .
______________________________________________
So,  solve for "x" and "y".

x = 68, y = 72 .
_______________________________________________
5 0
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