All categories

2 years ago

A = w + 5

Mathematics

1 answer:

san4es73 [151]2 years ago

4 0

Answer:

Step-by-step explanation:

a = w + 5

18 = w + 5 [subtract 5 from both sides of equation]

13 = w

You might be interested in

The points A (4, 0) and B (3, 7) are two vertices of right triangle ABC . The hypotenuse of the triangle is AB point C is on the

kenny6666 [7]

The point C must be in a line perpendicular tothe x-axis passing through the point B(3,7), then the oordinates of point C must be (3,0)

Answer: Coordinates of point C are (3,0)

6 0

3 years ago

What in slope-intercept form, can go through the line ( a, 2a) and (-5a, 6a)

Wittaler [7]

Answer:

y = -2/3x + 8/3a

Step-by-step explanation:

Given points

(a, 2a) and (-5a, 6a)

Slope-intercept form

y = mx + b

Slope of the line is

m = (6a - 2a)/( -5a - a) = 4a/(-6a) = - 2/3

The y-intercept is:

2a = -2/3*a + b
b = 2a + 2/3a
b= 8/3a

So the line is:

y = -2/3x + 8/3a

7 0

3 years ago

Read 2 more answers

5.3, CD r- 8.8, and AD - 14.3, find AB to the nearest tenth. If BC

pychu [463]

5.3/8.8=x/14.3
AB is x,
x= 2.43

Hope I helped.

7 0

3 years ago

Ron is selling items at a craft show. The first hour his sales are $20. His sales grow by 10% each hour. What are Ron's total sa

olga nikolaevna [1]

C. $122.10

20 first hour
20+0.1*20 = 22 second hour
22+0.1*22 = 24.2 third hour
24.2+0.1*24.2 = 26.62 fourth hour
26.62+0.1*26.62 = 29.282 fifth hour
Total=$122.10

5 0

3 years ago

Can someone explain the process getting from:

spin [16.1K]

$\rm 5=e^{3b}$

The unknown b is stuck in the exponent position.
We can can fix that by using logarithms.
Log is the inverse operation of the exponential.

We'll take log of each side.
Log of what base tho?

Well, the base of our exponential is e,
so we'll take log base e of each side.

$\rm log_e(5)=log_e(e^{3b})$

We'll apply one of our log rules next:
$\rm \log(x^y)=y\cdot\log(x)$

This allows us to take the exponent out of the log,

$\rm log_e(5)=(3b)log_e(e)$

Another thing to remember about logs:
When the base of the log matches the inside of the log,
then the whole thing is simply 1,
$\rm log_{10}(10)=1$
$\rm log_5(5)=1$
$\rm log_e(e)=1$

So our equation simplifies to this,

$\rm log_e(5)=(3b)\cdot1$

As a final step, divide both sides by 3,

$\rm \frac13log_e(5)=b$

k, hope that helps!

6 0

3 years ago