Answer:
Xà phòng hoá hoàn toàn 40,8 gam phenyl axetat trong dung dịch NaOH dư. Cô cạn dung dịch sau phản ứng thu được khối lượng muối làA. 59,4 g. B. 24,6 g. C. 39,6 g.D. 64,8 g.
Particles do not move solides have a definite shape and volume and cant flow by the particles that have been packed together.
Answer:
Explanation: For example, in a warm climate, where chemical weathering dominates, soils tend to ... including the mechanical breakup of rocks, and the chemical weathering of minerals. ... Too much water (e.g., in rainforests) can lead to the leaching of important ... it implies that the soil itself has been transported, which is not the case.
Given the mass percentage of Manganese in a normal healthy body is
It means that g Mn is present in 100 g of the body mass.
Given that the person weighs 196 lbs
Converting the person's mass to g: The conversion factors to be used are: 1 kg = 2.205 lb; 1 kg = 1000 g
Calculating the mass of Mn in the person's body:
Therefore, 0.116 g Mn is present in a person weighing 196 lbs.
Answer:
26.9 g
81%
Explanation:
The equation of the reaction is;
4 KO2(s) + 2 CO2(g) → 3 O2(g) + 2 K2CO3(s)
Number of moles of KO2= 27.9g/71.1 g/mol = 0.39 moles
4 moles of KO2 yields 2 moles of K2CO3
0.39 moles of KO2 yields 0.39 × 2/4 = 0.195 moles of K2CO3
Number of moles of CO2 = 57g/ 44.01 g/mol = 1.295 moles
2 moles of CO2 yields 2 moles of K2CO3
1.295 moles of CO2 yields 1.295 × 2/2 = 1.295 moles of K2CO3
Hence the limiting reactant is KO2
Theoretical yield = 0.195 moles of K2CO3 × 138.205 g/mol = 26.9 g
Percent yield = actual yield/theoretical yield × 100
Percent yield = 21.8/26.9 × 100
Percent yield = 81%