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ozzi
2 years ago
8

What happens to the boiling point of hydrocarbon compounds when the number of carbon atom increases

Chemistry
1 answer:
kumpel [21]2 years ago
3 0
The boiling points of alkanes increases with increasing number of carbons. This is because the intermolecular attractive forces, although individually weak, become cumulatively more significant as the number of atoms and electrons in the molecule increases.



So therefore your answer choice will increase. (B)
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I really need help with this!
Lady bird [3.3K]

Answer:

Explanation:

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8 0
3 years ago
After developing your hypothesis, the next step in the inquiry process is to design a controlled experiment in order to test you
Roman55 [17]
For your experiment, you would need to see decide what your hypothesis is before you design the experiment. If you want to see if the volume of gas changes depending on the container it's in, then you need to set it up depending on what you want to do with the volume.
The manipulated variable would be whatever you change, so if you switch container sizes, that would be the manipulated variable and the responding variable would be the volume of the gas.

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6 0
3 years ago
Someone help me on these two 2
prisoha [69]

Answer:

Question 4 is- Solubility

Question 5 is- Suspension

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6 0
2 years ago
A student dissolves 3.9g of aniline (C6H5NH2) in 200.mL of a solvent with a density of 1.05 g/mL . The student notices that the
Tresset [83]

Answer:

a. Molarity= M =2.1x10^{-1}M

b. Molality= m=2.0x10^{-1}m

Explanation:

Hello,

In this case, given the information about the aniline, whose molar mass is 93g/mol, one could assume the volume of the solution is just 200 mL (0.200 L) as no volume change is observed when mixing, therefore, the molarity results:

M=\frac{n_{solute}}{V_{solution}} =\frac{3.9g*\frac{1mol}{93g} }{0.2L} =2.1x10^{-1}M

Moreover, the molality:

m=\frac{n_{solute}}{m_{solvent}} =\frac{3.9g*\frac{1mol}{93g} }{0.2L*\frac{1.05kg}{1L} } =2.0x10^{-1}m

Best regards.

7 0
3 years ago
How can you find a tutor??​
yanalaym [24]

Depending on what you are doing, virtual, or in school, you can contact your school and you ask them, or you can have your teacher, based on the subject, tutor you.

<3

7 0
3 years ago
Read 2 more answers
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