In a chemical reaction, the products should always be equal to the reactants (in this case you would answer “the same as the reactants”) since we can neither create nor destroy matter (law of conservation!)
Hope this helps! :)
From the chemical formula, 1 formula unit of KAl (SO4)2.12H2O
encompasses 1 atom of Al = 4 * 2 atoms of O in KAl (SO4)2 + 12 atoms of O in
12H2O which is equal to 20 atoms of O.
So, if you have 1.3 × 10^21 Al atoms, you have 20 * 1.3 × 10^21 O atoms will
now be equal to 2.6 * 10^22 atoms of O.
Atomic mass Na = 22.99 u.m.a
22.99 g ------------------ 6.02x10²³ atoms
175 g -------------------- ?? atoms
175 x (6.02x10²³) / 22.99 => 4.58x10²⁴ atoms
hope this helps!
Answer:
we will take a 100g sample of this solution for our convenience
so , there is 15 g kBr in this 100g solution
we know that molality is the number if moles of solute / mass of solvent in kg
we need to find the number of moles in 15g kBr
no of moles = 15/119 s
moles = 0.126 moles/ 100g
multiplying both the numerator and the denominator by 10 to get 1 kg in denominator
= 1.26 moles / 1 kg
Hence, the molality is 1.26
would appreciate a brainliest
Answer:
54.75 mL
Explanation:
First calculate the number of moles of NaCl in the 150mL solution of NaCl
0.0365 moles should be present on 1000cm3 or 1dm3 of water.
1L = 1 dm3
1 mL = 1 / 1000 dm3
150 mL = 150/1000 dm3 = 0.15 dm3
If x moles are present in 0.15 dm3,
x/ 0.15 = 0.0365
We get x= 0.0365 × 0.15 mol
Now x amount of moles should be taken from the initial 0.100 M NaCl solution
So 0.1 moldm-3 = 0.0365× 0.15 mol / V
we get V = 0.05475 dm3
V= 0.05475 L
V= 54.75 mL
