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REY [17]
2 years ago
8

5. What is the value of x?

Mathematics
1 answer:
balu736 [363]2 years ago
4 0

Answer:

5\sqrt{3}

Step-by-step explanation:

in a 30-60-90 triangle the ratio of sides, respectively, is 1 : \sqrt{3} : 2

you can set up a proportion like this to solve for 'x':

\sqrt{3} / 1 = 15 / x

cross-multiply:

\sqrt{3}x = 15

x = 15/\sqrt{3}

rationalize the denominator by multiply top and bottom by \sqrt{3}

you get 15\sqrt{3} ÷ 3 which is 5\sqrt{3}

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Beth is making a rope ladder.each step of the ladder is 2 1/3 feet wide.Beth has a rope that is 21 feet long.how many steps can
Marianna [84]

Answer:

Beth can make 9 2 1/3 foot steps

Step-by-step explanation:

21/2.3=9.1

round to 9

7 0
2 years ago
Read 2 more answers
The square below represents a unit or a whole. What fraction is represented by the
Mkey [24]
20/28 or 10/14 or 5/7
You can keep reducing until both sides of the fraction can't be divided by the same number anymore.
5 0
2 years ago
mf help please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Andrej [43]

Answer:

Your answer is A.

Hope this helps!

Step-by-step explanation:

Line r's equation is

y = - 4/3x - 4

And Line s's equation is

y = 2/5x - 2

4 0
2 years ago
What is the inverse of the function shown?
Umnica [9.8K]

Answer:

The inverse is y = x + 5

Step-by-step explanation:

The general equation of a straight line is;

y = mx + c

In this case , the y-intercept is -5

So the partial equation is;

y = mx - 5

To get m, we use the x-intercept

The x-intercept coordinate is (5,0)

Insert this in the equation , we have;

0 = 5m-5

5m = 5

m = 5/5

m= 1

The equation of the line is thus;

y = x-5

So we want to find the inverse of this;

Replace x with d

y = d-5

Make d the subject of the formula

d = y + 5

replace d with x

x = y + 5

now replace x with y

So we have

y = x + 5

6 0
2 years ago
Assume that the lines that appear to be tangent are tangent p is the center if each circle find x. ​
Elodia [21]

Answer:

Step-by-step explanation:

Problem One

All quadrilaterals have angles that add up to 360 degrees.

Tangents touch the circle in such a way that the radius and the tangent form a  right angle at the point of contact.

Solution

x + 115 + 90 + 90 = 360

x + 295 = 360

x + 295 - 295 = 360 - 295

x = 65

Problem Two

From the previous problem, you know that where the 6 and 8 meet is a right angle.

Therefore you can use a^2 + b^2 = c^2

a = 6

b =8

c = ?

6^2 + 8^2 = c^2

c^2 = 36 + 64

c^2 = 100

sqrt(c^2) = sqrt(100)

c = 10

x = 10

Problem 3

No guarantees on this one. I'm not sure how the diagram is set up. I take the 4 to be the length from the bottom of the line marked 10 to the intersect point of the tangent with the circle.

That means that the measurement left is 10 - 4 = 6

x and 6 are both tangents from the upper point of the line marked 10.

Therefore x = 6

4 0
3 years ago
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