The experimental probability of each event is as follows:
- Landing open side up = 1/50 = 0.02 = 2%.
- Landing closed side up = 5/50 = 1/10 = 0.1 = 10%.
- Landing on its side = 44/50 = 0.88 = 88%.
The experimental probability of an event is the ratio of the number of outcomes that favored the event to the total number of outcomes in the experiment.
In the question, we are given that Jake tossed a paper cup 50 times and recorded the position how it landed, which is shown in the table:
Open-sided up: 1
Closed side up 5
On the side: 44.
We are asked to determine the experimental probability of each outcome.
The number of outcomes, when the landing is open-sided up is 1.
The number of outcomes, when the landing is closed-sided up is 5.
The number of outcomes, when the landing is on the side up is 44.
The total number of times the experiment took place is 50.
Thus, the experimental probability of each event is as follows:
- Landing open side up = 1/50 = 0.02 = 2%.
- Landing closed side up = 5/50 = 1/10 = 0.1 = 10%.
- Landing on its side = 44/50 = 0.88 = 88%.
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Area of the cage : A = L * W
A = 3 * 5
A = 15 sq ft....so ur cage is 15 square ft...and they need at least 12 sq ft...so yes, it is big enough
Answer:
x=-5
Step-by-step explanation:
Multiply both sides by 3:
Subtract 2x from both sides:
Divide both sides by 4:
Hope this helps!
Answer:
- Length of rectangle is 31 yards and Width is 24 yards.
Given:
- The length of a rectangle is 7 more than the width.
- The area is 744 sqaure yards
Solution:
Let's assume Width of rectangle be x and Length of rectangle be x + 7 respectively.
Using formula
On Substituting the required values, we get;
As we know that width of the rectangle can't be negative. So x = 24
<u>Hence</u>,
- Width of rectangle = x = 24 yards
- Length of the rectangle = x + 7 = 31 yards
Length of rectangle is 31 yards<u> </u>and Width is 24 yards.
Simplify
= 6/(gf^4)
hope that helps
