The question is incomplete. The complete question is :
The population of a certain town was 10,000 in 1990. The rate of change of a population, measured in hundreds of people per year, is modeled by P prime of t equals two-hundred times e to the 0.02t power, where t is measured in years since 1990. Discuss the meaning of the integral from zero to twenty of P prime of t, d t. Calculate the change in population between 1995 and 2000. Do we have enough information to calculate the population in 2020? If so, what is the population in 2020?
Solution :
According to the question,
The rate of change of population is given as :
in 1990.
Now integrating,

![$=\frac{200}{0.02}\left[e^{0.02(20)}-1\right]$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B200%7D%7B0.02%7D%5Cleft%5Be%5E%7B0.02%2820%29%7D-1%5Cright%5D%24)
![$=10,000[e^{0.4}-1]$](https://tex.z-dn.net/?f=%24%3D10%2C000%5Be%5E%7B0.4%7D-1%5D%24)
![$=10,000[0.49]$](https://tex.z-dn.net/?f=%24%3D10%2C000%5B0.49%5D%24)
=4900





This is initial population.
k is change in population.
So in 1995,



In 2000,


Therefore, the change in the population between 1995 and 2000 = 1,163.
12 is 75% of what
is means equals, of means multiply
12 = 75% * what
12 = .75 * what
divide each side by .75
12/.75 = .75 * what /.75
16 = what
12 is 75 percent of 16
the answer is 16
So for 1 1/3 you would go to 1 and count 3 lines after that and that is where you would plot it.
and for 2 4/9 you would count 4 lines after 2 but because there is only 6 lines you would divide by 2
30 divided by 60 is 1/2
1/2 miles per minute
10 x 1/2 = 5
5 miles in 10 minutes
Hope this helped