Answer:
Assign variables for unknowns.
Let A be the number of pounds of Type A coffee.
Let B be the number of pounds of Type B coffee.
A + B = 150 ( the total weight of the lend of Type A and Type B).
If one pound of Type A costs $4.15 then A pounds costs 4.15A
If one pound of Type B costs $5.60 then B pounds costs 5.6B
4.15A + 5.6B = 712.40 ( total cost of the blend)
At this point you have two equations with A and B as variables. You can use substitution or elimination method to solve for A.
A + B = 150
4.15A + 5.6B = 712.40
Substitution method:
A = 150 - B
4.15(150 - B) + 5.6B = 712.40
622.5 - 4.15B + 5.6B = 712.4
622.5 + 1.45B = 712.4
1.45B = 712.4 - 622.5
1.45B = 89.9
B = 89.9/1.45
B = 62
A = 150 - B
A = 150 - 62
A = 88
ANSWER: Elsa used 88 pounds of Type A blend.
Step-by-step explanation:
Assign variables for unknowns.
Let A be the number of pounds of Type A coffee.
Let B be the number of pounds of Type B coffee.
A + B = 150 ( the total weight of the lend of Type A and Type B).
If one pound of Type A costs $4.15 then A pounds costs 4.15A
If one pound of Type B costs $5.60 then B pounds costs 5.6B
4.15A + 5.6B = 712.40 ( total cost of the blend)
At this point you have two equations with A and B as variables. You can use substitution or elimination method to solve for A.
A + B = 150
4.15A + 5.6B = 712.40
Substitution method:
A = 150 - B
4.15(150 - B) + 5.6B = 712.40
622.5 - 4.15B + 5.6B = 712.4
622.5 + 1.45B = 712.4
1.45B = 712.4 - 622.5
1.45B = 89.9
B = 89.9/1.45
B = 62
A = 150 - B
A = 150 - 62
A = 88
ANSWER: Elsa used 88 pounds of Type A blend.
