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ahrayia [7]
3 years ago
12

Lena's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Lena $4.30 per pound, and type B

coffee costs $5.50 per pound. This month, Lena made 160 pounds of the blend, for a total cost of $806.80. How many pounds of type B coffee did she use?
Mathematics
1 answer:
Virty [35]3 years ago
4 0

Answer:

Assign variables for unknowns.

Let A be the number of pounds of Type A coffee.

Let B be the number of pounds of Type B coffee.

A + B = 150 ( the total weight of the lend of Type A and Type B).

If one pound of Type A costs $4.15 then A pounds costs 4.15A

If one pound of Type B costs $5.60 then B pounds costs 5.6B

4.15A + 5.6B = 712.40  ( total cost of the blend)

At this point you have two equations with A and B as variables.  You can use substitution or elimination method to solve for A.  

A + B = 150

4.15A + 5.6B =  712.40

Substitution method:

A = 150 - B

4.15(150 - B) +  5.6B = 712.40

622.5 - 4.15B + 5.6B = 712.4

622.5 + 1.45B = 712.4

1.45B = 712.4 - 622.5

1.45B = 89.9

B = 89.9/1.45

B = 62

A = 150 - B

A = 150 - 62

A = 88

ANSWER: Elsa used 88 pounds of Type A blend.

Step-by-step explanation:

Assign variables for unknowns.

Let A be the number of pounds of Type A coffee.

Let B be the number of pounds of Type B coffee.

A + B = 150 ( the total weight of the lend of Type A and Type B).

If one pound of Type A costs $4.15 then A pounds costs 4.15A

If one pound of Type B costs $5.60 then B pounds costs 5.6B

4.15A + 5.6B = 712.40  ( total cost of the blend)

At this point you have two equations with A and B as variables.  You can use substitution or elimination method to solve for A.  

A + B = 150

4.15A + 5.6B =  712.40

Substitution method:

A = 150 - B

4.15(150 - B) +  5.6B = 712.40

622.5 - 4.15B + 5.6B = 712.4

622.5 + 1.45B = 712.4

1.45B = 712.4 - 622.5

1.45B = 89.9

B = 89.9/1.45

B = 62

A = 150 - B

A = 150 - 62

A = 88

ANSWER: Elsa used 88 pounds of Type A blend.

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2 years ago
The quadratic function h(t) = -16.1? + 150 models a ball's height, in feet, over time, in seconds,
Sliva [168]
<h2>Hello!</h2>

The answer is: The first graphic representation.

<h2>Why?</h2>

We are given a quadratic equation, meaning that it could be two possible solutions for the exercise, however, we are talking about time, so we have to consider only the obtained positive values.

Let's make the equation equal to 0 in order to find the values of "t"

h(t) = -16.1t^2 + 150

0=-16.1t^2+150

16.1t^2=150

t^2=\frac{150}{16.1} =9.32

t=+-\sqrt{9.32} =+-3.05

t1=3.05

t2=-305

So, discarding the negative value, we can use the possitive value to find the correct graphic representation.

To find the correct graphic representation we must take into consideration the following:

- We must remember that the sign of the coefficient of the quadratic term (t^2) will define if the parabola opens downward or upward.

From the given quadratic (or parabola) equation we have:

a=-1

b=0

c=150

So, since the coefficient of the quadratic term is negative, the parabola opens downward.

- Since we are looking for a graphic that represents the change in height over time, we need to look for a graphic that shows only positive values for the x-axis (time)

- We are looking for a parabola which y-axis intercept is equal to 150.

Therefore, the graphic representation of the quadratic function that models a ball's height over time is the first graphic representation.

Have a nice day!

5 0
2 years ago
I definitely need help, big time. What's the step by step solution to this math problem -(80/-10)^2?
mojhsa [17]
The final answer is -64
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3 years ago
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