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rodikova [14]
3 years ago
9

HELP WILL MARK BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! 98 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
problems. Thinking too much into it.?
The parents teachers association at your school donated school supplies to help increase student creativity and student success in the classroom. Your teacher would you to create kits that include one package of colored pencils, one glue stick, and one ruler. When you receive the supplies, you notice the colored pencils are packaged 12 boxes to a case, the rulers are packaged 30 to a box, and glue sticks are packaged 4 to a box.

1. What is the smallest number of each supply you will need in order to make kits and not have supplies left over? Explain your though process.

2. How many packaged rulers, colored pencils, and glue sticks will you need in order to make the kits? Explain the process you used to determine how Many packages are needed for each supply.
Mathematics
1 answer:
il63 [147K]3 years ago
8 0

Divide all package numbers by 2:

30 / 2 = 15 Rulers

12 / 2 = 6 Colored Penicils

4 / 2 = 2 Glue Sticks

2.

15 + 6 + 2 = 23

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780 as a percentage of 1.5
Anna [14]
780 as a percentage of 1.5
=\frac{780}{1.5} *100
=52,000 percent of 1.5
4 0
3 years ago
Please I need help I don't understand
mario62 [17]

Answer:

Step-by-step explanation:

from the graph of f(x)

when x=1,f(x)=0

or f(1)=0

when f(x)=2,x=2

for g(x)

when x=6,g(x)=16

or g(6)=16

when g(x)=18,x=32

for h(x)

when x=14

h(x)=27x-7

h(14)=27×14-7=7(27×2-1)=7(54-1)=7×53=371

h(x)=-493

27x-7=-493

27 x=-493+7=-486

3 x=-54

x=-18

for p(t)

when t=94

p(t)=24

p(94)=24

p(t)=67

t=31

8 0
3 years ago
The equations -6x + 3y = 6 and x² + y = 10 intersect at the
eimsori [14]

The values of the letters in coordinates (a, b) and (c,d) are;

<u><em>a = -4</em></u>

<u><em>b = -6</em></u>

<u><em>c = 2</em></u>

<u><em>d = 6</em></u>

<u><em /></u>

We are given two equations;

-6x + 3y = 6  ---(eq 1)

x² + y = 10 ---(eq 2)

  • We are told that they intersect at coordinates; (a, b) and (c, d).

Let us make y the subject in eq 2 to get;

y = 10 - x²  --(eq 3)

  • Let us put 10 - x² into eq 1 to get;

-6x + 3(10 - x²) = 6

expanding further gives;

-6x + 30 - 3x² = 6

rearranging gives;

3x² + 6x - 24 = 0

Using online quadratic equation <em>solver</em>, we have;

x = -4 and x = 2

Putting x = -4 into eq 3 gives;

y = 10 - (-4)²

y = 10 - 16

y = -6

Putting x = 2 into eq 3 gives;

y = 10 - (2)²

y = 10 - 4

y = 6

  • Thus, the coordinates are; (-4, -6) and (2, 6)

Comparing with (a, b) and (c,d), we have;

a = -4

b = -6

c = 2

d = 6

Read more at; brainly.com/question/15165519

5 0
3 years ago
What are two equivalent ratios of 12:7
kozerog [31]
24:14 and 36:21 are both equivalent ratios to 12:7
4 0
3 years ago
Read 2 more answers
Find the simplified product b-5/2b x b^2+3b/b-5
White raven [17]

Answer:

The product \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}

Step-by-step explanation:

Given expression \frac{b-5}{2b} and \frac{b^2+3b}{b-5}

We have to find the product of  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}

   

Consider the given expression  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}

Multiply fractions, we have,

\frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d}

=\frac{\left(b-5\right)\left(b^2+3b\right)}{2b\left(b-5\right)}

Cancel common factor ( b - 5 )

we have, =\frac{b^2+3b}{2b}

Apply exponent rule,

\:a^{b+c}=a^ba^c

b^2=bb

=bb+3b=b(b+3)

=\frac{b\left(b+3\right)}{2b}

Cancel common factor b , we have,

=\frac{b+3}{2}

Thus, the product  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}

8 0
4 years ago
Read 2 more answers
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