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The dimensions of the rectangular pen should be 15 by 20 feet and the maximum area is 1200 square feet.
Let the area be y .
Area = (base) × (height)
Base = 2x
Height = h
Let the area of the rectangular pens be y .
∴ y = 2xh
Perimeter of all the fencing = 4x+3h
∴ 4x+3h = 120
now we solve for h
3h = 120-4x
h = 40 - 4/3 x
Now we will substitute this value in the above first equation:
y = 2xh
or, y = 2x (40 - 4/3 x)
or, y = 80x - 8/3 x²
Now for the maximum area we have to find the first order differentiation of y
now,
dy /dx = 80 - 16/3 x
At dy/dx = 0 we get the value of x for which y is maximum.
80 - 16/3 x = 0
or, - 16/3 x = -80
or, x = 15 feet
Hence height = 40 - 4/3 x = 40 - 20 = 20feet
Maximum area = 2xh = 2×15×40 = 1200 square feet
The dimensions of the rectangular pen should be 15 by 20 feet and the maximum area is 1200 square feet.
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Answer: The answer is D. P(t) = - 16t^2 + 100t / 3.2808
Step-by-step explanation:
(i) Note that it is given to you that 3a + 2b = 9
You are trying to find the value of 9a + 6b. Find what is multiplied to both the variable a & b. Divide:
(9a + 6b)/(3a + 2b) = 3
Next, multiply 3 to the 9 on the other side of the equation:
3 x 9 = 27
27 is the value of 9a + 6b.
(ii) Note that it is given to you that 8x + 6y = 60
You are trying to find the value of 4x + 3y. Find what is multiplied to both the variable x & y. Divide:
(8x + 6y)/(4x + 3y) = 2
Next, divide 2 from the 60 on the other side of the equation:
60/2 = 30
30 is the value of 4x + 3y.
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Answer:
they can be any shape the baker wants to be.