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Vladimir [108]
3 years ago
15

Please help me

Mathematics
2 answers:
Nastasia [14]3 years ago
6 0

Answer:

180

Step-by-step explanation:

Nady [450]3 years ago
4 0
I believe they are congruent.
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A Sea-doo rental agency charges $100 as a flat rate, and $50 for every hour rented. Complete a table of values for this scenario
Julli [10]

Answer:

so if it was one hour it would be 100+50

2 hours= 100+100

3=100+ 150

and so on

Step-by-step explanation:

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3 years ago
Suraj took a slice of pizza from the freezer and put it in the oven. The pizza's temperature (in degrees Celsius) as a function
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It took about 0.5 minutes to reach level 0
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The license plates on all karts in MarioLand contain three numbers followed by three letters. If you know that the MarioLand num
UNO [17]

Answer:

1575 license plates with at least one three piece palindrome

Step-by-step explanation:

Fon know the number of license plates that have at least one three piece palindrome is necessary to identify the following cases:

  • There is palindrome in the 3 numbers and not in the 3 letters of the license plate: A three piece palindrome happens when the first and the last number is the same. So we can calculate the number of ways in which this can happen using the rule of multiplication as:

<u>__5__      _</u>*<u>__5___</u>* <u>__1___</u>* <u>__3___   </u>*   <u>__3___</u>*    <u>__2__</u>_  =  450

1st number    2nd         3rd        1st letter        2nd            3rd

The MarioLand number system has 5 digits so the are 5 options for the first and second number, then if we want a palindrome, the 3rd number has to be the same of the first so the 3rd number just have one option.

Additionally, the MarioLand letter system has 3 letters, so we have 3 options for first and second number but we don't want a palindrome in the letters, so the 3rd letter need to be a number different of the first, that means that it has 2 options.

At the same way we calculate the number of possibilities in the following cases:

  • There is palindrome in the 3 letters and not in the 3 numbers of the license plate: There are 900 different ways that apply for this case, this is calculate as:

<u>__5__      _</u>*<u>__5___</u>* <u>__4___</u>* <u>__3___   </u>*   <u>__3___</u>*    <u>__1__</u>_  =  900

1st number    2nd         3rd        1st letter        2nd            3rd

  • There is palindrome in the 3 letters and in the 3 numbers of the license plate: There are 225 different ways that apply for this case, this is calculate as:

<u>__5__      _</u>*<u>__5___</u>* <u>__1___</u>* <u>__3___   </u>*   <u>__3___</u>*    <u>__1__</u>_  = 225

1st number    2nd         3rd        1st letter        2nd            3rd

Finally the total number of license plate that can be created with at least one three piece palindrome is the sum of the possibilities of the three cases:

450+900+225=1575

4 0
4 years ago
X + 2 2/1=10<br> HELPPPPPPP!!!!!!!!!!!!!!!!!
irakobra [83]

Answer:

  • x+4=10
  • x=6
  • Give brainlist
3 0
3 years ago
17. In a spelling competition, school X had 12 more participants than school Y and 18 fewer participants than school Z. The rati
Elan Coil [88]

There were 204 participants from the three schools

<h3>How to determine the number of participants?</h3>

The given parameters are:

X = 12 + Y

X = Z - 18

Girls = Boys + 50

The ratios of the number of boys to girls in the schools are:

1 : 2

1 : 5

2 : 1

This means that:

  • School X: Boys = 1/3 and Girls = 2/3
  • School Y: Boys = 1/6 and Girls = 5/6
  • School Z: Boys = 2/3 and Girls = 1/3

So, we have:

Boys = 1/3X + 1/6Y + 2/3Z

Girls = 2/3X + 5/6Y + 1/3Z

Substitute the above equations in Girls = Boys + 50

2/3X + 5/6Y + 1/3Z = 1/3X + 1/6Y + 2/3Z + 50

Evaluate the like terms

1/3X + 2/3Y - 1/3Z = 50

Multiply through by 3

X + 2Y - Z = 150

So, we have:

X = 12 + Y

X = Z - 18

X + 2Y - Z = 150

Substitute X = 12 + Y in X = Z - 18 and X + 2Y - Z = 150

12 + Y = Z - 18 ⇒ Y - Z = 30

12 + Y + 2Y - Z = 150 ⇒ 3Y - Z = 138

Subtract Y - Z = 30 from the equation 3Y - Z = 138 to eliminate Z

2Y = 108

Divide by 2

Y = 54

Substitute Y = 54 in X = 12 + Y

X = 12 + 54

X = 66

Substitute X = 66 in X = Z - 18

66 = Z - 18

Solve for Z

Z = 66 + 18

Z = 84

So, the total number of participants from the 3 schools is

Total = X + Y + Z

This gives

Total = 66 + 54 + 84

Evaluate the sum

Total = 204

Hence, there were 204 participants from the three schools

Read more about system of equations at:

brainly.com/question/14323743

#SPJ1

8 0
2 years ago
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