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Wewaii [24]
3 years ago
12

Two companies, A and B, drill wells in a rural area. Company A charges a flat fee of 3681 dollars to drill a well regardless of

its depth. Company B charges 1168 dollars plus 10 dollars per foot to drill a well. The depths of wells drilled in this area have a normal distribution with a mean of 260 feet and a standard deviation of 40 feet. Find the probability that Company B would charge more than Company A to drill a well.
Mathematics
1 answer:
jekas [21]3 years ago
3 0

Answer:

Mean costing =  $3,768

Step-by-step explanation:

Given:

Mean A(x) = 260

Rate = $10 per feet

Fixed charge = $1,168

Computation:

Assume;

depth = x ft

So,

Cost of company B = 10x + 1,168

So,

Mean costing = 10A(x) + 1,168

Mean costing =  10(260) + 1,168

Mean costing =  2,600 + 1,168

Mean costing =  $3,768

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TiliK225 [7]
The <u>correct answers</u> are:

16) Mean = 10.25; Median = 10; Range = 17
17) The range.
18) 10
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Explanation:

16) To find the <u>mean</u>, we first find the sum of the data values in the set:
5+5+6+6+7+8+8+8+9+9+10+10+10+10+10+11+12+12+12+13+13+15+15+22 = 246.

Next we divide this sum by the number of data points, 24:
246/24 = 10.25.

The <u>median</u> is the middle point of a data set.  Since there are 24 points, this will be between two values.  These two values are 10 and 10; the median is 10.

The <u>range </u>is found by subtracting the highest and lowest values:
22-5 = 17.

17) The <u>mean </u>is changed; the sum of the data values is 246.  Taking 22 out of this, the sum is now 223, and we have 23 data points instead of 24; 223/23 = 9.7 for the new mean.
The <u>median </u>does not change; it is still 10.
The <u>range</u> changes; the highest value is now 15, and the lowest is 5:  15-5=10.  The range is changed the most.

18) The <u>mean is affected</u> by the outlier and the <u>median is not</u>, so we use the <u>median</u>.  This means the answer is 10.

19) The expression for the total number of cars sold is found by adding together all of the points.
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Answer:

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