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Orlov [11]
2 years ago
11

Which decimals are equivalent to

Mathematics
1 answer:
jenyasd209 [6]2 years ago
5 0

Therefore, the decimal equivalent to the expression (5 \times 10) + (2 \times \frac{1}{100} ) is 50.02

The given expression is:

(5 \times 10) + (2 \times \frac{1}{100} )

Note that \frac{1}{100} = 0.01

The expression therefore becomes:

(5  x  10)   +  (2  x  0.01)

50   +  0.02

= 50.02

Therefore, the decimal equivalent to the expression (5 \times 10) + (2 \times \frac{1}{100} ) is 50.02

Learn more here: brainly.com/question/18770964

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Simplify the expression. ​
deff fn [24]

(6^-2)^2

When you have a number raised to a power inside parenthesis and then it is raised to another power, to simplify, multiply the two powers together:

-2 x 2 = -4

Simplified is 6^-4

5 0
3 years ago
Read 2 more answers
Geometry Question Help if you can please
docker41 [41]

Answer:

≈ 78.55 cm

Step-by-step explanation:

Using the ratio of arc (AB) to circumference (C) is equal to the ratio of angle subtended at centre by arc AB to 360°, that is

\frac{AB}{C} = \frac{110}{360} , that is

\frac{24}{C} = \frac{110}{360} ( cross- multiply )

110C = 8640 ( divide both sides by 110 )

C = \frac{8640}{110} ≈ 78.55 cm ( to 2 dec. places )

5 0
3 years ago
1) UN MOVIL A SE MUEVE DESDE UN PUNTO CON VELOCIDAD CONSTANTE DE 20m/s EN EL MISMO INSTANTE A UNA DISTANCIA DE 1200m, OTRO MOVIL
alisha [4.7K]

Answer:

El móvil B necesita 60 segundos para alcanzar al móvil A y le alcanza una distancia de 2400 metros con respecto al punto de referencia.

Step-by-step explanation:

Supóngase que cada movil viaja en el mismo plano y que el móvil B se localiza inicialmente en la posición x = 0\,m, mientras que el móvil A se encuentra en la posición x = 1200\,m. Ambos móviles viajan a rapidez constante. Si el móvil B alcanza al móvil A después de cierto tiempo, el sistema de ecuaciones cinemáticas es el siguiente:

Móvil A

x_{A} = 1200\,m+\left(20\,\frac{m}{s} \right)\cdot t

Móvil B

x_{B} = \left(40\,\frac{m}{s} \right)\cdot t

Donde:

x_{A}, x_{B} - Posiciones finales de cada móvil, medidas en metros.

t - Tiempo, medido en segundos.

Si x_{A} = x_{B}, el tiempo requerido por el móvil B para alcanzar al móvil A es:

1200\,m+\left(20\,\frac{m}{s} \right)\cdot t = \left(40\,\frac{m}{s} \right)t

1200\,m = \left(20\,\frac{m}{s} \right)\cdot t

t = \frac{1200\,m}{20\,\frac{m}{s} }

t = 60\,s

El móvil B necesita 60 segundos para alcanzar al móvil A.

Ahora, la distancia se obtiene por sustitución directa en cualquiera de las ecuaciones cinemáticas:

x_{B} = \left(40\,\frac{m}{s} \right)\cdot (60\,s)

x_{B} = 2400\,m

El móvil B alcanza al móvil A a una distancia de 2400 metros con respecto al punto de referencia.

3 0
3 years ago
О с. А о.
timurjin [86]

Answer:

Step-by-step explanation:

To be parallel the slopes must be equal

4x-3y=15

3y=4x-15

y=(4x-15)/3

so m=4/3

Only line D. has a slope of 4/3

7 0
3 years ago
Read 2 more answers
Juan is painting the floor of an outdoor racquetball court. He knows that 1 gallon of paint will cover the shaded area shown bel
Ahat [919]

Answer:oof Juan is painting the floor of an outdoor racquetball court. He knows that 1 gallon of paint will cover the shaded area shown below. If it takes Juan 3h hours to apply 1 gallon of paint, approximately how many hours will it take him to paint the entire court? Show your work or explain in words.

Step-by-step explanation:

6 0
3 years ago
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