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aleksandr82 [10.1K]
3 years ago
7

Drag and drop the correct angle measures onto the diagram

Mathematics
1 answer:
svlad2 [7]3 years ago
7 0

Answer:

Here you go!

Hope this helps!

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PLS, I NEED HELP! Translate this sentence into a compound inequality with math symbols.
Vlada [557]

Answer:

8o F at least I'm pretty sure 101o F ≥ 8o

Step-by-step explanation:

Correct me If im wrong

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Barry wants to open a checking account. He wants online services, and a debit card. He is looking at the following tables of fee
Alla [95]

Answer:

ITS B 78 Bucks

Step-by-step explanation:

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3 years ago
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Brooke earned $34 for 4 hours . Write an equation to show her total wages, w, for h hours of work
elena-14-01-66 [18.8K]
4w=34 would be the correct equation if I’m understanding what the question is asking!
6 0
3 years ago
6 3/8+5 1/3 what is the answer and how do you figure it out
inn [45]

Answer:

11 17/24

Step-by-step explanation:

To find this out we have to first find out the least common denominator for 8 and 3 which would be 24, now we have to switch both denominators to 24 but also have to switch the numerators to how much we multiplied the denomintors by and then add. so we multiplied 8 by 3 to get it to 24 so we multiply the numerator 3 by 3 as well. and for the second fraction we multiply the denominator 3 by 8 to get 24 so we multiply the nuerator by 8 as well. so...

6 3/8+ 5 1/3= 6 9/24 + 5 8/24 = 11 17/24

8 0
3 years ago
Estimate the perimeter and area of the shaded figure to the nearest tenth.
Maru [420]

Answer:

Perimeter = 18.7 units

Area = 13.5 units²

Step-by-step explanation:

Perimeter of ADEC = AD + DE + EC + AC

Length of AD = 3 units

By applying Pythagoras theorem in ΔDBE,

DE² = DB² + BE²

DE² = 3² + 3²

DE = √18

DE = 4.24 units

Length of EC = 3 units

By applying Pythagoras theorem in ΔABC,

AC² = AB² + BC²

AC² = 6² + 6²

AC = √72

AC = 8.49 units

Perimeter of ADEC = 3 + 4.24 + 3 + 8.49

                                 = 18.73 units

                                 ≈ 18.7 units

Area of ADEC = Area of ΔABC - Area of ΔBDE

Area of ΔABC = \frac{1}{2}(AB)(BC)

                       = \frac{1}{2}(6)(6)

                       = 18 units²

Area of ΔBDE = \frac{1}{2}(BD)(BE)

                       = \frac{1}{2}(3)(3)

                       = 4.5 units²

Area of ADEC = 18 - 4.5

                        = 13.5 units²

6 0
3 years ago
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