Is it −26−(6)^2? If so
−26−(6)^2
= -26 - 36
= - 62
If −26−(6)2 (means 6 times 2) then
= -26 - 12
= -38
Answer:
the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.
Step-by-step explanation:
From the given question.
Let p be the length of the of the printed material
Let q be the width of the of the printed material
Therefore pq = 2400 cm ²
q = 
To find the dimensions of the poster; we have:
the length of the poster to be p+30 and the width to be 
The area of the printed material can now be: 
=
Let differentiate with respect to p; we have

Also;

For the smallest area 


p² = 3600
p =√3600
p = 60
Since p = 60 ; replace p = 60 in the expression q =
to solve for q;
q =
q = 
q = 40
Thus; the printed material has the length of 60 cm and the width of 40cm
the length of the poster = p+30 = 60 +30 = 90 cm
the width of the poster =
=
= 40 + 20 = 60
Hence; the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.
Answer:
Steps below
Step-by-step explanation:
The value depends on which angle is B, suppose ∠B is the opposite angle of side length 7
sin B = 7/25
cos B = 24/25
tan B = 7/24
if ∠B opposite to side length of 24
sin B = 24/25
cos B = 7/25
tan B = 24/7