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vaieri [72.5K]
3 years ago
12

The expression

x^{1/2}y^{-2/3})^-6 " alt="( x^{1/2}y^{-2/3})^-6 " align="absmiddle" class="latex-formula"> is equivalent to
A. \frac{y^4}{x^3}
B. \frac{x^3}{y^4}
C. \frac{1}{x^3y^4}
D. x^3y^4

Please Show All Work
Mathematics
1 answer:
forsale [732]3 years ago
8 0
Y ^(-2/3)^-6 = y^12/3 = y^4

x^(1/2)^ -6 = x^-3 = 1 x^3

so the answer is y^4 * 1 /x^3  = y^4 / x^3

A
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If the standard deviation of an exam is 5, the z-score us 1.95 and the mean is 80; what is the actual test score? (Round the ans
skad [1K]

If the standard deviation of an exam is 5, the z-score us 1.95 and the mean is 80, the actual test score is; 89.75

<h3>How to solve z-score problems?</h3>

We are given;

Standard deviation; s = 5

z-score = 1.95

Mean = 80

Formula for z-score is;

z = (x' - μ)/σ

Thus;

1.95 = (x' - 80)/5

1.95 * 5 = (x' - 80)

9.75 = x' - 80

x' = 80 + 9.75

x' = 89.75

Read more about Z-score Problems at; brainly.com/question/25638875

#SPJ1

6 0
1 year ago
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Georgia [21]
Answer:

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Step-by-step explanation:

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3 years ago
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A pet store has 15 birds and 75 fish.
Ludmilka [50]

Answer:

1/5

Step-by-step explanation:

6 0
2 years ago
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Greg has collected 4,385 pennies and Hannah has collected 3,899 pennies. How many times as great as the value of 3 in 4,385 is t
wel
Answer: The 3 in 3,899 is 10 times the 3 in 4,385!
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The repair cost of a Subaru engine is normally distributed with a mean of $5,850 and a standard deviation of $1,125. Random samp
Yuri [45]

Answer:

C. $5180

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Z-scores lower than -2 or higher than 2 are considered unusual.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random normally distributed variable X, with mean \mu and standard deviation \sigma, the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 5850, \sigma = 1125, n = 20, s = \frac{1125}{\sqrt{20}} = 251.56

Which of the following mean costs would be considered unusual?

We have to find the z-score for each of them

A. $6350

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{6350 - 5850}{251.56}

Z = 1.99

Not unusual

B. $6180

Z = \frac{X - \mu}{s}

Z = \frac{6180 - 5850}{251.56}

Z = 1.31

Not unusual

C. $5180

Z = \frac{X - \mu}{s}

Z = \frac{5180 - 5850}{251.56}

Z = -2.66

Unusual, and this is the answer.

3 0
3 years ago
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