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Alborosie
2 years ago
8

Could yall help me PLEASE

Mathematics
1 answer:
klasskru [66]2 years ago
3 0

Answer: 3.6

Step-by-step explanation:

(Not the best at math but I am an above level student)

C= pi x diameter

C= pi x 1.205

C= 3.7

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Find 1/4+13/20<br> . Write your answer as a fraction in simplest form.
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3 years ago
Suppose that the weights of passengers on a flight to Greenland on Frigid Aire Lines are normal with mean 175 pounds and standar
Natali5045456 [20]

Answer:

The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 175, \sigma = 22

What is the minimum weight for a passenger who outweighs at least 90% of the other passengers?

90th percentile

The 90th percentile is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. So

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 175}{22}

X - 175 = 22*1.28

X = 203.16

The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds

6 0
3 years ago
I need help with this question it's for a important grade so pls really help.​
iogann1982 [59]

Answer:

Check pdf

Step-by-step explanation:

Download pdf
4 0
3 years ago
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