The numbers are 105 and 50
<em><u>Solution:</u></em>
Let "x" be the first number
Let "y' be the second number
Twice a number plus twice a second number is 310
Therefore,
twice of x + twice of y = 310
2x + 2y = 310 ---------- eqn 1
The difference between the numbers is 55
x - y = 55 -------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 2,
x = 55 + y ------ eqn 3
<em><u>Substitute eqn 3 in eqn 1</u></em>
2(55 + y) + 2y = 310
110 + 2y + 2y = 310
4y = 310 - 110
4y = 200
<h3>y = 50</h3>
<em><u>Substitute y = 50 in eqn 3</u></em>
x = 55 + 50
<h3>x = 105</h3>
Thus the numbers are 105 and 50
Answer:
-5 x -2 = 10
Step-by-step explanation:
- x - = +
5 x 2 = 10
Answer: 3
Step-by-step explanation:
1. Convert the mixed number to fraction:
- Multiply the denominator of the fraction by the whole number.
- Add the product obtained and the numerator of the fraction.
- Write the sum obtained as the numerator and rewrite the original denominator of the fraction.
Then:
2. Multiply the numerators.
3. Multiply the denominator.
4. Reduce the fraction.
Then:
