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Serggg [28]
3 years ago
8

I need help with this question

Mathematics
1 answer:
expeople1 [14]3 years ago
8 0
Its t-h
because the sinB = AC/AB (=h) and the cosB= CB/AB but the sinA = CB/AB and the cosA =AC/AB
=> SinB = CosA= t; CosB = sinA=h
=>SinA-CosA = t-h
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Please answer question now
kirill [66]

Answer:

\overrightarrow{VU}\text{ and }\overrightarrow{VW}

Step-by-step explanation:

From the given figure it is clear that we two rays because both sides have one endpoint and goes on infinitely in only one direction.

If a ray has end point at A and goes on infinitely in only one direction towards point B, then ray is denoted as \overrightarrow{AB}.

For first side, we have point V as end point and ray goes goes on infinitely in only one direction towards point U. So, first side is \overrightarrow{VU}.

For second side, we have point V as end point and ray goes goes on infinitely in only one direction towards point W. So, second side is \overrightarrow{VW}.

Therefore, the sides are \overrightarrow{VU}\text{ and }\overrightarrow{VW}.

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Answer: I think a

Step-by-step explanation:

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Find the coordinates of point R on QS such that the ratio of QR to<br> RS is 1.2
lisabon 2012 [21]

Answer:

The points P, Q, R and S all lie on the same line segment, in that order, such that the ratio of PQ : QR: RS is equal to 4:2:1.

Step-by-step explanation:

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The answer will be letter C 
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For the function f(x) = x2 + 3, find the slope of the tangent line at x = 11.
Vika [28.1K]

Given:

The function is

f(x)=x^2+3

To find:

The slope of the tangent line at x = 11.

Solution:

The slope of the tangent is the value of f'(x) at x=11.

We have,

f(x)=x^2+3

Differentiate with respect to x.

f'(x)=2x+0              \left[\because \dfrac{d}{dx}x^n=nx^{n-1},\dfrac{d}{dx}C=0,\text{ where C is constant}\right]

f'(x)=2x

Substitute x=11 in the above equation.

f'(11)=2(11)

f'(11)=22

Therefore, the slope of the tangent at x=11 is 22.

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