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2 years ago

Special right triangles!!! Help

Mathematics

2 answers:

klemol [59]2 years ago

8 0

Answer:

This is a 30, 60, 90, right triangle.

The length of the longest side (this case s), is equal to twice the length of the shortest side.

x $\sqrt{3\\}$ = 27

x = 27/ $\sqrt{3}$

s is twice as that, so the answer is 54/ $\sqrt{3}$

Let me know if this helps!

Archy [21]2 years ago

3 0

Answer:

i think 40 meters

Step-by-step explanation:

i hope this helps

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Answer please Fast Fast

solong [7]

Answer:

A. 228.5

B. 10

Step-by-step explanation:

A. Since x represents the number of months, replace x with 6 in the equation. Then multiply 29x6, which equals 174. Then add 174+54.5, which equals 228.5.

B. You need to solve for x by switching the signs in the equation. Set the original equation (29x+54.5) equal to 344.50. To solve for x, first subtract 344.50-54.5, which equals 290 (you subtract because it's the opposite of adding). Then divide 290÷29, which equals 10. You can check your work by replacing x in the original equation with 10, and if you get 344.5, your answer is correct.

Good luck :)

6 0

3 years ago

You bike 1 mile the first day of your training, 1.3 miles the second day, 1.9 miles the third day, and 3.1 miles the fourth d

JulsSmile [24]

Answer:

19.9 miles

Step-by-step explanation:

In this problem we have:

$d_1=1 mi$ is the distance travelled during the 1st day

$d_2=1.3 mi$ is the distance travelled during the 2nd day

$d_3=1.9 mi$ is the distance travelled during the 3rd day

$d_4=3.1 mi$ is the distance travelled during the 4th day

We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

$d_2-d_1=0.3\\d_3-d_2=2\cdot 0.3 = 0.6\\d_4-d_3=2\cdot 0.6 = 1.2$

Which can be rewritten using the general formula:

$d_{n+1}-d_n=2(d_n-d_{n-1})$

This means that

$d_{n+1}=d_n+2(d_n-d_{n-1})$

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

$d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi$

So, the distance travelled on the 7th day is 19.9 miles.

7 0

3 years ago

How to graph x+y=1 & is it linear

liq [111]

Answer:

Step-by-step explanation:

Plot the points x-intercept and intercept on the graph. Join the two points to get the straight line. This is the graph of the linear equation.

7 0

3 years ago

Can anyone help me figure out how to do this

3241004551 [841]

Answer:

$133m^2$

Step-by-step explanation:

What if i say NO?

3*3=9

8+3=11

12-3=9

9*11=99

2 area coverd so far

99+9=108

7*2=14

108+14=122

Lastly the tir

10-7=3

11-3-2=6

6*4=24

24/2=12

$133m^2$

8 0

3 years ago

Cherie is jogging around a circular track. She

skelet666 [1.2K]

Answer:

Measure of minor angle JOG is $95.5^{\circ}$

Step-by-step explanation:

Consider a circular track of radius 120 yards. Assume that Cherie starts from point J and runs 200 yards up to point G.

$\therefore m JG = 200 yards, JO=120 yards$ .

Now the measure of minor arc is same as measure of central angle. Therefore minor angle is the central angle $\angle JOG = \theta$ .

To calculate the central angle, use the arc length formula as follows.

$Arc\:Length\left(s\right) = r\:\theta$

Where $\theta$ is measured in radian.

Substituting the value,

$200=120\:\theta$

Dividing both side by 120,

$\dfrac{200}{120}=\theta$

Reducing the fraction into lowest form by dividing numerator and denominator by 40.

$\therefore \dfrac{5}{3}=\theta$

Therefore value of central angle is $\angle JOG = \theta=\left(\dfrac{5}{3}\right)^{c}$ , since angle is in radian

Now convert radian into degree by using following formula,

$1^{c}=\left(\dfrac{180}{\pi}\right)^{\circ}$

So multiplying $\theta$ with $\left(\dfrac{180}{\pi}\right)^{\circ}$ to convert it into degree.

$\left(\dfrac{5}{3}\right)^{c}=\left(\dfrac{5}{3}\right) \times \left(\dfrac{180}{\pi}\right)^{\circ}$

Simplifying,

$\therefore \theta = 95.49^{circ}$

So to nearest tenth, $\angle JOG=95.5^{circ}$

8 0

3 years ago