Answer:
See step by step answer
Step-by-step explanation:
the factors are (x+22)(x-10)=0
so x = -22 and 10, but a dimension cannot be negative, so the answer for x is 10 and then if you plug it back in the dimensions are 4 cm, 11 cm and 21 cm.
When you multiply 4 * 11 * 21 = 924, so you know it's correct.
X=weekly allowance
x/2=money saved (= money spent).
We can suggest this equation:
x/2+4=12
lowest common multiple=2
x+8=24
x=24-8
x=16
Answer: her weekly allowance is $16.
Answer:
The ball reached its maximum height of (
) in (
).
Step-by-step explanation:
This question is essentially asking one to find the vertex of the parabola formed by the given equation. One could plot the equation, but it would be far more efficient to complete the square. Completing the square of an equation is a process by which a person converts the equation of a parabola from standard form to vertex form.
The first step in completing the square is to group the quadratic and linear term:
![h(t)=-5t^2 + 10t + 6\\\\h(t) = (-5t^2 + 10t) + 6](https://tex.z-dn.net/?f=h%28t%29%3D-5t%5E2%20%2B%2010t%20%2B%206%5C%5C%5C%5Ch%28t%29%20%3D%20%28-5t%5E2%20%2B%2010t%29%20%2B%206)
Now factor out the coefficient of the quadratic term:
![h(t)=-5(t^2 -2t) + 6](https://tex.z-dn.net/?f=h%28t%29%3D-5%28t%5E2%20-2t%29%20%2B%206)
After doing so, add a constant such that the terms inside the parenthesis form a perfect square, don't forget to balance the equation by adding the inverse of the added constant term:
![h(t) = -5(t^2 -2t) + 6\\\\h(t) = -5(t^2 -2t + 1 -1 ) + 6](https://tex.z-dn.net/?f=h%28t%29%20%3D%20-5%28t%5E2%20-2t%29%20%2B%206%5C%5C%5C%5Ch%28t%29%20%3D%20-5%28t%5E2%20-2t%20%2B%201%20-1%20%29%20%2B%206)
Now take the balancing term out of the parenthesis:
![\\\\h(t)=-5(t^2 -2t + 1) + 6 + ((-1)(-5))](https://tex.z-dn.net/?f=%5C%5C%5C%5Ch%28t%29%3D-5%28t%5E2%20-2t%20%2B%201%29%20%2B%206%20%2B%20%28%28-1%29%28-5%29%29)
Simplify:
![h(t) = -5(t^2 -2t + 1) + 6 + 5\\\\h(t) = -5(t-1)^2 + 11](https://tex.z-dn.net/?f=h%28t%29%20%3D%20-5%28t%5E2%20-2t%20%2B%201%29%20%2B%206%20%2B%205%5C%5C%5C%5Ch%28t%29%20%3D%20-5%28t-1%29%5E2%20%2B%2011)
The x-coordinate of the vertex of the parabola is equal to the additive inverse of the numerical part of the quadratic term. The y-coordinate of the vertex is the constant term outside of the parenthesis. Thus, the vertex of the parabola is:
![(1, 11)](https://tex.z-dn.net/?f=%281%2C%2011%29)
Answer A is the only one that seems to make sense to me id choose A