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IgorLugansk [536]
2 years ago
7

A jar contains four yellow balls, six red balls, and eight blue balls. One ball is selected at random.

Mathematics
2 answers:
uysha [10]2 years ago
8 0

Answer:

Step-by-step explanation:

We are trying to see how likely we are to pick a yellow ball. So out of the total number of balls, we have 4 yellow balls (numerator). The total number of balls is 18 and so the probability of picking a yellow ball is 4/18

wlad13 [49]2 years ago
3 0

Answer:

4/18

Step-by-step explanation:

1. you would first take all the number of colored balls and add them together

2. next, you would take the number of yellow balls/ to the total number of balls.

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Anyone can help me solve this equation using cross multiplying
Natali5045456 [20]

9514 1404 393

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  x = 1 or 5

Step-by-step explanation:

The notion of "cross-multiplying" is the idea that the numerator on the left is multiplied by the denominator on the right, and the numerator on the right is multiplied by the denominator on the left. This looks like ...

  \displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\ \longrightarrow\ (x-1)(3x-1)=(7)(2x-2)

Then the solution proceeds by eliminating parentheses, and solving the resulting quadratic equation.

  3x^2-4x+1=14x-14\\\\3x^2-18x+15=0\qquad\text{subtract $14x-14$}\\\\x^2-6x+5=0 \qquad\text{divide by 3}\\\\(x-1)(x-5)=0\qquad\text{factor}\\\\x\in\{1,5\}

_____

<em>Comment on "cross multiply"</em>

Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes <em>what the result looks like</em>. It doesn't adequately describe how you get there. The <em>one and only rule</em> in solving Algebra problems is "<em>whatever is done to one side of the equation must also be done to the other side of the equation</em>." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.

What looks like "cross multiply" is really "<em>multiply by the product of the denominators</em> and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.

  \displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\\\\\frac{x-1}{7}\times7(3x-1)=\frac{2x-2}{3x-1}\times7(3x-1)\\\\(x-1)(3x-1)=(2x-2)(7)\qquad\textit{looks like}\text{ cross multiply}

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Oksanka [162]
The answer is 7.3 or in other words 7 3/10

Hope I helped
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