Answer:
Probability that both cats described will have an offspring who is heterozygous for both traits is 50%, according to the scenario given.
Explanation:
When a cat amazing and bashful is crossed with a cat average and boring, it is a crossing where two traits are taken into account that will be segregated independently by the parents, and the result can be obtained by analyzing their genotypes and making the corresponding crossing in a Punnett square.
<u>Genotypes</u>:
- <u>Male cat</u> AABb
- <u>Female cat
</u> aabb
<u>Crossing</u>
:
Punnett's square (simplified)
<em>Alelles AB Ab</em>
<em>ab AaBb Aabb</em>
<em>ab AaBb Aabb</em>
<u>Offspring</u>:
- <em>AaBb amazing and bashful (heterozygous for two traits) 50%</em>
- <em>Aabb amazing and boring (heterozygous for trait A ans homozygous recessive for B) 50%</em>
<u><em>Probability that they will have an offspring who is heterozygous for both traits is 50%.</em></u>
The net gain of ATP molecules per molecule of glucose in the reactions of glycolysis is 2.
Glucose is the main source of almost all energy used by cells of similar and different organisms.
In glycolysis process, the production of two pyruvate molecules, a net gain of two ATP molecules, and two NADH molecules takes place.
Answer:
The nucleus contains the protons and neutrons which takes up most of the mass of the atom.
<span>A symbiotic relationship in which one organism lives inside the other and both organisms benefit is the correct answer </span>
