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3 years ago

Having a fair coin i.e. P(Head) = P(Tail) = 0.5, what is the probability of getting a sequence of 3 consecutive tails?

Computers and Technology

1 answer:

Andrews [41]3 years ago

5 0

Answer:

Probability of getting 3 consecutive tails in a fair coin toss:-

P(E)=0.125

Explanation:

If we toss an unbiased coin exactly three time we can have 8 outputs possible and those outputs are as following:-

HHH
HHT
HTH
HTT
THH
THT
TTH
TTT

Out of these 8 outputs we have 1 favorable outcome that is TTT.So the probability of the event is P(E)=1/8

where 8 is total number of outcomes.

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Answer:

by signing into the wifi network they have

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3 years ago

3. The wildlife department has been feeding a special food to rainbow trout finger lings in a pond. A sample of the weight of 40

andrey2020 [161]

Answer:

1) 402.7 grams. This estimate is called the sample mean.

2) (399.11, 406.29)

3) The 99 percent confidence limits is between 399.11 grams and 406.29 grams.

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Explanation:

sample size (n) = 40, the mean weight (x)= 402.7 grams and the standard deviation (σ)=8.8 grams

1) The point estimated mean weight of the population is 402.7 grams. This estimate is called the sample mean.

2) c = 99% = 0.99

α = 1 - 0.99 = 0.01

$\frac{\alpha }{2} =\frac{0.01}{2} =0.005$ .

The z score of 0.005 corresponds with the z score of 0.495 (0.5 - 0.005).

$z_\frac{\alpha }{2} =2.58$ .

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The confidence interval = x ± e = 402.7 ± 3.59 = (399.11, 406.29)

3) The 99 percent confidence limits is between 399.11 grams and 406.29 grams.

I am 99% sure that the value lies between 399.11 grams and 406.29 grams.

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3 years ago

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Answer:

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3 years ago

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LenKa [72]

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3 years ago