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zysi [14]
3 years ago
11

15z+35=50 what is the answer to this

Mathematics
2 answers:
Inga [223]3 years ago
7 0

Answer:

z = 1

Step-by-step explanation:

15z + 35 = 50

15z = 50 - 35

15z = 15

z = 15/15

z = 1

ss7ja [257]3 years ago
6 0

Answer:

  1. z = 1

Step-by-step explanation:

15z+35=50

15z=50-35

15z=15

15z÷15=15÷15

z=1

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The quadrilaterals ABCD and JKLM are similar.<br> Find the length x of LM.
babunello [35]

Answer:

it is 2

Step-by-step explanation:

beacause CD is quadrilateral with LM

5 0
3 years ago
Use the long division method to find the result when x^3+7x^2+12x+6x 3 +7x 2 +12x+6 is divided by x+1x+1. If there is a remainde
Aliun [14]

Answer:

By long division (x³ + 7·x² + 12·x + 6) ÷ (x + 1) gives the expression;

x^2 + 5 \cdot x + 7 - \dfrac{1}{(x + 1)}

Step-by-step explanation:

The polynomial that is to be divided by long division is x³ + 7·x² + 12·x + 6

The polynomial that divides the given polynomial is x + 1

Therefore, we have;

\ \ \ \ \ \  \ \ \ \ \ \ x^2 + 5\cdot x + 7\\ (x + 1) \sqrt{x^3 + 7\cdot x^2 +12\cdot x + 6} \\\ {} \  {} \ {}  \  \ {} \  {} \ {}  \ {} \  {} \ {}   \ {}     \ \ x^3 + 2 \cdot x^2 \\\  \ \ \ {} \   \ {} \  {} \ {}   \  \ {} \ {} \  \   \ {} \  {} \ {}  \  \ {} \  {} \ {}  \ \ 5 \cdot x^2 + 12\cdot x + 6\\  \ {} \  {} \ {}    \ {} \  {} \ {}  \ \ {} \ {} 5 \cdot x^2 + 5\cdot x\\\ 7\cdot x+6\\7\cdot x+7\\-1

(x³ + 7·x² + 12·x + 6) ÷ (x + 1) = x² + 5·x + 7 Remainder -1

Expressing the result in the form q(x) + \dfrac{r(x)}{b(x)}, we have;

(x^3 + 7\cdot x^2 + 12 \cdot x + 6)\div (x + 1) =  x^2 + 5 \cdot x + 7 - \dfrac{1}{(x + 1)}

4 0
3 years ago
For the function, find all critical numbers and then use the second-derivative test to determine whether the function has a rela
Serhud [2]

Answer:

relative maximum: x = 1

relative minimum: x = 7

Step-by-step explanation:

Critical points:

Values of x for which f'(x) = 0.

Second derivative test:

For a critical point, if f''(x) > 0, the critical point is a relative minimum.

Otherwise, if f''(x) < 0, the critical point is a relative maximum.

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

f(x) = x^{3} - 12x^{2} + 21x - 8

Finding the critical points:

f'(x) = 3x^{2} - 24x + 21

3x^{2} - 24x + 21 = 0

Simplifying by 3

x^{2} - 8x + 7 = 0

So a = 1, b = -8, c = 7

\bigtriangleup = (-8)^{2} - 4*1*7 = 36

x_{1} = \frac{-(-8) + \sqrt{36}}{2} = 7

x_{2} = \frac{-(-8) - \sqrt{36}}{2} = 1

Second derivative test:

The critical points are x = 1 and x = 7.

The second derivative is:

f''(x) = 6x - 24

f''(1) = 6*1 - 24 = -18

Since f''(1) < 0, at x = 1 there is a relative maximum.

f''(7) = 6*7 - 24 = 18

Since f''(x) > 0, at x = 7 there is a relative minumum.

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3 years ago
Equivalent measures for 8 fl oz are ?
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If you are looking for gallons then its 0.0625
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4 years ago
How do I solve this using substitution?
oksano4ka [1.4K]

Answer :y=4   x=2

Step-by-step explanation:

8 0
3 years ago
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