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SOVA2 [1]
3 years ago
7

F(a) =-3a + 3; Find f(10)

Mathematics
1 answer:
Slav-nsk [51]3 years ago
3 0

Answer:

-27

Step-by-step explanation:

f(a) = -3a + 3

f(10) = -3(10) + 3

= -30 + 3

= -27

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Add all like terms.
50x + 11

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Two angles are supplementary. The first angle is 3x degrees. The second angle is (2x+25) degrees. Determine the measure of the s
Alex17521 [72]
A = 3x
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What is the value of y when -5 =<br> = y - 7?<br> 9<br> a. -7<br> b.-11<br> C. -38<br> d. -52
weqwewe [10]

Answer:

2

Step-by-step explanation:

You have to cancel the -7 so you would add +7 to each side.

-7+7=0, -5+7= 2

y=2

Although this isn't an answer choice. Did you mistype something?

8 0
3 years ago
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by
11111nata11111 [884]

Answer:

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is V=l\times b\times h

V=(11-2x)\times (7-2x)\times x

V=4x^3-36x^2+77x

Derivate w.r.t x,

V'(x)=4(3x^2)-2(36x)+77

V'(x)=12x^2-72x+77

The critical point when V'(x)=0

12x^2-72x+77=0

Solve by quadratic formula,

x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}

x=4.607,1.392

Derivate again w.r.t x,

V''(x)=24x-72

Now, V''(4.607)=24(4.607)-72=38.568>0 (+ve)

V''(1.392)=24(1.392)-72=-38.592 (-ve)

So, there is maximum at x=1.392.

The length of the box is l=11-2x

l=11-2(1.392)=8.216

The breadth of the box is b=7-2x

b=7-2(1.392)=4.216

The height of the box is h=1.392.

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is V=l\times b\times h

V=8.216\times 4.216\times 1.392

V=48.217\ in.^3

The volume of the box is 8.217 cubic inches.

5 0
3 years ago
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