???????????????(this is how far I got)
Place value. when multiplying by 10 you are moving a decimal, having everything lined up like place value would save you a lot of time.
Answer:
x = 2
Step-by-step explanation:
'x' can represent the hypotenuse of a right triangle with a base of 4 (11-7) and a height of 2
use Pythagorean Theorem to find 'x':
2² + 4² = x²
4 + 16 = x²
x² = 20
x = 
x =
·
x = 2
Answer:
98 is the answer of the expression
Step-by-step explanation:
AS it is a simple algebraic expression so these are solved by BDMAS rule which means that we have to solve the brackets first starting from the smaller bracket first which is inside a larger bracket then we will move to Division then multiplication then addition and then subtraction
so the following equation can be written as
= ![2^{3}[\frac{1}{4}+4(36/12)]](https://tex.z-dn.net/?f=2%5E%7B3%7D%5B%5Cfrac%7B1%7D%7B4%7D%2B4%2836%2F12%29%5D)
First of all solving smallest bracket and division inside it
= ![2^{3}[\frac{1}{4}+4(3)]](https://tex.z-dn.net/?f=2%5E%7B3%7D%5B%5Cfrac%7B1%7D%7B4%7D%2B4%283%29%5D)
Multplying 4 inside
= ![2^{3}[\frac{1}{4}+12]](https://tex.z-dn.net/?f=2%5E%7B3%7D%5B%5Cfrac%7B1%7D%7B4%7D%2B12%5D)
Now solving the 2³
= ![8[\frac{1}{4}+12]](https://tex.z-dn.net/?f=8%5B%5Cfrac%7B1%7D%7B4%7D%2B12%5D)
Now solving the expression inside the bracket by taking LCM
= ![8[\frac{1 + 4*12}{4}]](https://tex.z-dn.net/?f=8%5B%5Cfrac%7B1%20%2B%204%2A12%7D%7B4%7D%5D)
= ![8[\frac{1 + 48}{4}]](https://tex.z-dn.net/?f=8%5B%5Cfrac%7B1%20%2B%2048%7D%7B4%7D%5D)
= ![8[\frac{49}{4}]](https://tex.z-dn.net/?f=8%5B%5Cfrac%7B49%7D%7B4%7D%5D)
Now multiplying 8 with inside values
= ![[\frac{8*49}{4}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B8%2A49%7D%7B4%7D%5D)
AS 8 cuts out with 4 so
= 2 * 49
= 98
which is the answer of the expression