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gogolik [260]
3 years ago
12

The grade on a paper decreases by 5 points each day that it is late with a starting value of 87 points.

Mathematics
1 answer:
stellarik [79]3 years ago
7 0

Answer:

I don't know but if you want to me follow please follow me

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For each equation below , determine the value of y if x = 2 .
Fynjy0 [20]
You simply plug in the value of x in each equation to find y.

1)
y = 7 - 3(2)
y = 7 - 6
y = 1

2)
y = 18/2
y = 9

hope this helped, blessings!
3 0
3 years ago
Read 2 more answers
Lines e and f are parallel. The mAngle9 = 80° and mAngle5 = 55°. Parallel lines e and f are cut by transversal c and d. All angl
loris [4]

Answer:

The angle measures that are correct are m<2 = 125degrees, m<8 = 55 degrees and m<14 = 100 degrees

Given the following angles from the diagram;

m<5 = 55 degrees

m<9 = 80degrees

From the diagram

m<5 = m<1 = 55 degrees (corresponding angle)

m<1 + m<2 = 180 (sum of angle on a straight line)

Hence;

55 + m<2 = 180

m<2 = 180 - 55

m<2 = 125degrees

Also;

m<5 = m<8 = 55 degrees (vertically opposite angle)

m<9 = m<13 = 80degrees

m<13 + m<14 = 180

Hence;

80 + m<14 = 180

m<14 = 180 - 80

m<14 = 100 degrees

Hence the angle measures that are correct are m<2 = 125degrees, m<8 = 55 degrees and m<14 = 100 degrees

Step-by-step explanation:

7 0
2 years ago
Rewrite using standard notation : 8.07 x 10^3
sammy [17]
8070, because when it is a positive exponent you have to move the exponent to the right. When it is a negative exponent, you would move it to the left. Hope this helps :)
4 0
3 years ago
Researchers recorded the speed of ants on trails in their natural environments. The ants studied, Leptogenys processionalis, all
posledela

This question is Incomplete

Complete Question

Researchers recorded the speed of ants on trails in their natural environments. The ants studied, Leptogenys processionalis, all have the same body size in their adult phase, which made it easy to measure speeds in units of body lengths per second (bl/s). The researchers found that, when traffic is light and not congested, ant speeds vary roughly Normally, with mean 6.20 bl/s and standard deviation 1.58 bl/s. (a) What is the probability that an ant's speed in light traffic is faster than 5 bl/s? You may find Table B useful. (Enter your answer rounded to four decimal places.)

Answer:

0.7762

Step-by-step explanation:

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score

μ is the population mean

σ is the population standard deviation.

Population mean = 6.20 bl/s

Standard deviation = 1.58 bl/s.

x = 5 bl/s

z = 5 - 6.20/1.58

z = -0.75949

The probability that an ant's speed in light traffic is faster than 5 bl/s is P( x > 5)

Probability value from Z-Table:

P(x<5) = 0.22378

P(x>5) = 1 - P(x<5)

= 1 - 22378

= 0.77622

Approximately to 4 decimal places = 0.7762

The probability that an ant's speed in light traffic is faster than 5 bl/s is 0.7762

5 0
3 years ago
Write the rule to describe the translation.
lara31 [8.8K]

Answer:rqs

Step-by-step explanation:

7 0
4 years ago
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